Problem 1428. Find the optimal shape to bring the maximum product by a given perimeter

Created by Eliad

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Solution Stats

157 Solutions
41 Solvers

Last Solution submitted on Jan 11, 2023

Last 200 Solutions

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10 Comments

10 Comments

Show 7 older comments

Ryan on 17 Apr 2013

I can't get the test suite to work.
Anyone else having a problem?
I appear to get the exact same answers.

Michael C. on 17 Apr 2013

The function is setup the wrong way by default. You actually have to return a vector with Nopt as the first element and the product as the second. When he calls the function in the test suite, it will return only Nopt the way the function is originally setup with two outputs.

Eliad on 19 Apr 2013

I have made the problem a little bit more challenging by changing only the test suite.
The propose is to get a math solution.
The leading solver has already made it.

James on 23 Apr 2013

If the purpose is to get a math solution, why play tricks with how the output needs to be passed and read?

Eliad on 23 Apr 2013

No tricks.
Math solution is always better than brute force solution.
if you choose bruth - your solution may be limited by the number of iterations.

James on 24 Apr 2013

Sorry, I should have been clearer with my previous comment. Yes, there is a math solution to this problem that does not require brute force. Solutions 231885-231887 are mine, and give the correct (mathematical) answers with no brute forcing at all. However, because of the way the output needs to be passed to the assert function, they are marked as wrong by Cody. Other than the odd way that the output needs to be parsed, this is a great problem.

goc3 on 24 Feb 2017

The test suite has been updated to avoid the problems mentioned by James.

John D'Errico on 26 Mar 2018

I took a look at the test cases. The 4th test has a result that is expected to be on the order of 1e40. Then it compares that to the solution returned, and tests to see if the absolute difference is less then 1e-4? eps(1e40) is roughly 1e24. So the difference between two numbers of size 1e40 will never be less than 1e-4, unless they are IDENTICAL. Far better would be to test if the relative difference is small.

John D'Errico on 26 Mar 2018

I updated the problem explanation to be a bit more clear. I also repaired the checks for a valid solution to use a relative test, mainly valuable for one of the cases where an absolute test on the error was a poor choice.

J. S. Kowontan on 12 Apr 2018

Clearly, the best score comes from older solvers not having to deal with singularity that occurs when p = 5, which was not included in the test suite back then.

Solution Comments

Solution 231891

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1 Comment

Eliad on 19 Apr 2013

Best solution!

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