saving or not matrices

2 Ansichten (letzte 30 Tage)
Nicolas
Nicolas am 21 Jun. 2011
Hi,
I'm looking for a way of saving matrices depending on their content.
My loop is generating matrices that I want to save, however sometimes there is no proper values in it (only zeros that i replace by NaN).
I'd like to save only the matrices that have at least one proper value (> 0), but not the ones that have only zeros or NaN.
cheers
  1 Kommentar
manoj saini
manoj saini am 21 Jun. 2011
if a(:)~=0
%save matrix
end

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Matt Fig
Matt Fig am 21 Jun. 2011
if ~all(isnan(A(:)))
% Do the saving.
end
But it seems to me that if the only source of nans is from when you replace the zeros with nans, then why not just skip this step and decide to save it based on whether the whole array is not equal to zero?
if any(A(:)) % Array with even one non-zero element passes.
% Do the saving.
end
  1 Kommentar
Nicolas
Nicolas am 21 Jun. 2011
oh yeah, that's better.. didn't know "any" though! thanks

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Nicolas
Nicolas am 21 Jun. 2011
Actually I found that way
barycenter(barycenter(:,:)==0)=NaN; %replace zeros with NaN
if isnan(barycenter(1:1))<1
Names = sprintf('%s-%d', FileName, N(n));
xlswrite(Names, barycenter)
end
any advices?
  2 Kommentare
Matt Fig
Matt Fig am 21 Jun. 2011
Your method only checks if the first element is nan or not. It looks like you could learn to benefit from linear indexing. For example,
A(A(:)==0) = nan; % Index all elements at once with (:)
Nicolas
Nicolas am 21 Jun. 2011
actually if at least a value appears in my matrix, then it has to be in the first cell, that's why I put ..(1,1). thanks for the tip though

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by