How to form an array of sums?

2 Ansichten (letzte 30 Tage)
Yuval
Yuval am 19 Okt. 2013
Kommentiert: Anthony am 20 Okt. 2013
Hi, I am asked to evaluate the following sum S=Sigma(n=0 to N) x^n/n! (namely, e^x as n->Inf) for N=10:10:100 and x=10, so that every element S(i) is a partial sum which approximates function e^x with different accuracy. Below is my code, which doesn't work:
x=10; N=10:10:100; S=symsum(x^n/sym('n!'), n, 0, N)
Would anyone please tell me where I am going wrong and how it may be corrected? I'd appreciate some guidance.

Antworten (1)

Anthony
Anthony am 19 Okt. 2013
Bearbeitet: Anthony am 19 Okt. 2013
syms n;
x=10;
N=100;
% N cannot be a vector (if you want N=10:10:100, use a loop instead.)
S=double(symsum(x^n/sym('n!'), n, 0, N))
  2 Kommentare
Yuval
Yuval am 19 Okt. 2013
Hi Anthony, Thank you very much for your reply. I am now trying the following, albeit, alas, it still does not quite work:
x=10; N=10; i=0; while (N<=100), S(i)=double(symsum(x^n/sym('n!'), n, 0, N)); i=i+1; N=N+10; end
Could you please advise?
Anthony
Anthony am 20 Okt. 2013
Bearbeitet: Anthony am 20 Okt. 2013
add 'syms n;', and initialize i=1 instead of 0.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Mathematics finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by