Could I extract an specific column from a table and then use it in a loop without name it (variable)?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
DulceEien
am 15 Aug. 2021
Kommentiert: DulceEien
am 15 Aug. 2021
I'm wondering if I can use directly the column (extracted from a matrix) inside the loop, for example or should I name if first because T1(:,8)(i) does not work
A = zeros(length(T1(:,7)),length(T2(:,7)));
for i=1:length(T1(:,7))
for ii=1:length(T2(:,7))
idx(i,ii) = ( abs((T1(:,8)(i)-T2(:,8)(i))))
end
end
0 Kommentare
Akzeptierte Antwort
Walter Roberson
am 15 Aug. 2021
h1 = height(T1); h2 = height(T2);
A = zeros(h1, h2);
for i = 1 : h1
for ii = 1 : h2
A(i,ii) = abs(T1{i,8} - T2{i,8});
end
end
However... you might as well use
A = abs(T1{:,8} - T2{:,8}.');
with no loop, provided you have R2015b or later.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!