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How can I apply an auto-correlation to a Radon Transformation?

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Andrei
Andrei am 10 Okt. 2013
Kommentiert: Matt J am 14 Okt. 2013
I have the following code
I = imread('img.jpg');
I = rgb2gray(I);
theta = 1:180;
[R,xp] = radon(I,theta);
how can I apply auto-correlation on this radon transformation on an image?
I have the following formula for auto-correlation which I want to apply:
where g(s,0) is the radon transformation. How can I implement this in Matlab? or is there an equivalent function that I can use?
Thank you in advance!

Akzeptierte Antwort

Matt J
Matt J am 10 Okt. 2013
Bearbeitet: Matt J am 10 Okt. 2013
Just apply conv() or xcorr(), if you have it, to each of the columns of R. A simple for-loop will do.

Weitere Antworten (1)

Matt J
Matt J am 10 Okt. 2013
Bearbeitet: Matt J am 10 Okt. 2013
You can also use Fourier methods, something like
c=ifft( fft(R).*conj(fft(R)) )
c=bsxfun(@rdivide,c,sum(R.^2,1));
  3 Kommentare
Bjorn Gustavsson
Bjorn Gustavsson am 14 Okt. 2013
Just shooting from the hip on this one. In principal the results should be the same, within numerical accuracies- but if you use xcorr it might give you some default weigthing of the different lags.
Matt J
Matt J am 14 Okt. 2013
The correlation/convolution, when implemented using ffts, is circulant. You will have to zero pad to make it equivalent to linear convolution.

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