How to have a just specific part of a plot?

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shahin sharafi
shahin sharafi am 13 Aug. 2021
Kommentiert: shahin sharafi am 14 Aug. 2021
Hi
For a purpose, I am trying to have a just specific part of my plot only. For example, if you run the below code, you will get figre 1 (attached file), but I want have just part of it that has been shown in figure 2 (attached file). I dont mean about using axis function (axis([0,18000,0,2000]);). I want to eliminate other part of the plot after plotting.
Thank you in advance for you help.
Regards,
Shahin
clear all
clc
% close all
%%
m=60;L=1;J=60;g=9.81;beta2=411.67;
Time_Delayb=0.2;Time_Delaye=0.25;
tau1=Time_Delayb;tau2=Time_Delaye;
KPb=2.15;KDb=0.75;
%%
W = linspace(0, 10*pi, 1000);omega=W;
Kpe=@(omega)J.*cos(omega.*tau2).*omega.^2 - KDb.*beta2.*omega.*sin(omega.*tau1 - omega.*tau2) + L.*cos(omega.*tau2).*g.*m - KPb.*beta2.*cos(omega.*tau1 - omega.*tau2);
Kde=@(omega)(omega.^2.*J.*sin(omega.*tau2) - KDb.*beta2.*omega.*cos(omega.*tau1 - omega.*tau2) + m.*g.*L.*sin(omega.*tau2) + KPb.*beta2.*sin(omega.*tau1 - omega.*tau2))./omega;
%%
figure('DefaultAxesFontSize',10,'DefaultAxesFontName','Times')
D_Curve_PD_KPe=Kpe(omega);
D_Curve_PD_KDe=Kde(omega);
%%
plot(D_Curve_PD_KPe,D_Curve_PD_KDe,'color',[1 0.025 0.05],'LineWidth', 2)
grid on
hold on

Akzeptierte Antwort

Scott MacKenzie
Scott MacKenzie am 13 Aug. 2021
Bearbeitet: Scott MacKenzie am 13 Aug. 2021
Follow the plot command with...
axis([0 400 0 120]);
axis off;
set(gcf,'color','w');
Output:
  3 Kommentare
Scott MacKenzie
Scott MacKenzie am 13 Aug. 2021
Bearbeitet: Scott MacKenzie am 13 Aug. 2021
Well, in that case, I'm not really sure what you are trying to do.
Are you trying to get just a portion of the curve? If so, something like this might work, assuming you know the start and end indices of the section of the curve of interest:
% plot(D_Curve_PD_KPe,D_Curve_PD_KDe,'color',[1 0.025 0.05],'LineWidth', 2)
startIdx = 400;
endIdx = 600;
x = D_Curve_PD_KPe(startIdx:endIdx);
y = D_Curve_PD_KDe(startIdx:endIdx);
plot(x,y,'color',[1 0.025 0.05],'LineWidth', 2);
shahin sharafi
shahin sharafi am 14 Aug. 2021
Thank yo so much for your help .

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