Why do I get an error when I try to write data into file?

I want to write "Formattyp = 1" into my file Batch.csv.

This is the section of my code:

myBatchName = '\\\\data-be\\data-ti-2019\\eit\\50_Labore\\T016-Photovoltaik_1\\06_Projekte\\02_Aktiv\\2019_Schenker_Storen\\DOCS_Hannah\\Experiment2\\02_Generate_Batch_File\\02-EXP2_Batch_Files\\Batch.csv';
fileID = fopen(myBatchName,'w'); %open file for writing; discard existing contents
fprintf(fileID,'Formattyp = 1\n');

But I keep getting this error:

" Error using fprintf

Invalid file identifier. Use fopen to generate a valid file identifier.

Error in EXP2_Ver1_Generate_Batch_File (line 111)

fprintf(fileID,'Formattyp = 1\n'); "

Which I do not understand because I have specified my fileID, so it should know where to write the data into. What am I doing wong? Thanks.

[Stephen23]

"...so it should know where to write the data into."

And what should MATLAB do if that path or file does not exist? Specifying the file ID does not tell us anything about if the path exists. Rather than just guessing what the problem is, it is much simpler to get FOPEN to tell you why it could not open that file:

[fileID,msg] = fopen(myBatchName,'w'); 
assert(fid>=3,'%s',msg)

Hint: get rid of those duplicated backslashes, and don't forget FCLOSE at the end.

[Hannah]

Thanks, yeh it works when I remove the duplicated backslashes.

Now i'm wondering why sometimes duplicated backslashes are needed when specifying a path e.g. when 'sprintf' is used. How can I know when to use duplicated backslashes?

Answer 1

[KSSV]

Check the path of the file....check the value of fileID. If the file is not open properly, the value will be negative. There is probem with your filename/ path.