# how to access elements of a vector inside a cell array

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Chiara Scarpellini on 11 Aug 2021
Edited: Dave B on 11 Aug 2021
I need to access with a for loop all the elements of SimulatedPoints but I struggle with finding the notation. This is what I did but it returns the entire vector of the cell.
for j=1:length(SimulatedPoints.Codes{idxRow,:})
end
Stephen23 on 11 Aug 2021
Edited: Stephen23 on 11 Aug 2021
"how to access elements of a vector inside a cell array"
What cell array?
Your screenshot shows a 2785x3 table containing strings and numeric values. I do not see any cell array.

Dave B on 11 Aug 2021
The length part should return the entire contents of the cell, so your code looks fine to me. Inside the loop you'd refer to the individual elements of the cell:
name=["a";"b"];
codes=[{rand(3,1);rand(5,1)}];
t=table(name,codes)
t = 2×2 table
name codes ____ ____________ "a" {3×1 double} "b" {5×1 double}
row = 2;
for i = 1:length(t.codes{row})
disp(t.codes{row}(i))
end
0.3208 0.7280 0.7743 0.9703 0.6213
##### 2 CommentsShowHide 1 older comment
Dave B on 11 Aug 2021
Edited: Dave B on 11 Aug 2021
@Stephen Cobeldick - My answer is an offical TMW announcement of anything, I just jump on answers sometimes to help out when I'm not too busy. But personally, I certainly don't think of tables and cell arrays as the same, they seem quite different in many regards (although you can convert between them quite easily). I didn't mean to jump into something controversial.
In this example there's clearly a cell, you can see it in the disp, and isa(t.codes(2),'cell') returns true. So t.codes{row} returns the contents of the cell t.codes(row), right?

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