plot phase angle in radian

subplot(2,2,1)
%chi=1; alpha=2; lambda=0.25
%eta=0
p1=0.00139;
%eta=10
p2=-0.01262;
theta_rad = p1*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%==========================================================
subplot(2,2,2)
theta_rad = p2*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,3)
%alpha=2; lambda=0.25
%eta=0
p3=0.02877;
%eta=10
p4=0.25253;
theta_rad = p3*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,4)
theta_rad = p4*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

[Walter Roberson]

I am not sure what the question is? Are you asking to have the polar plot labeled in radians instead of degrees?

[Shreen El-Sapa]

I recalculate the above as the following? my question now what are the values that appear on the figure

subplot(2,2,1)
%chi=1; alpha=2; lambda=0.25
%eta=0
p1=0.00139;
%eta=10
p2=-0.01262;
theta_rad = p1*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%==========================================================
subplot(2,2,2)
theta_rad = p2*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,3)
%alpha=2; lambda=0.25
%eta=0
p3=0.02877;
%eta=10
p4=0.25253;
theta_rad = p3*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,4)
theta_rad = p4*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

[Shreen El-Sapa]

I asked about the yellow highlighted in the attached figure

[Walter Roberson]

Yes?

You are using polar() with a single parameter. The default when you pass a single parameter to polar() is to treat the input as radii, with equally-spaced angles (dividing a full circle by the number of radii passed in.)

The numbers you outlined in yellow are the radii you passed in. You converted some input value to radians according to your comments, so the radius of each polar plot represents radians for something. That all seems like something that you might want to do, so I do not see what you would like to have happen differently ?

[Shreen El-Sapa]

I asked about the highlighted numbers only. you clearified.Thanks.

[Walter Roberson]

To be more correct, the yellow numbers are linear spaced from 0 to the maximum value you asked to plot.

Answer 1

[Walter Roberson]

If the question is about switching the polar plot degrees to radians, then change your calls to polar() to instead be calls to polarplot(), and set the option 'ThetaAxisUnits', 'radians'

https://www.mathworks.com/help/matlab/ref/matlab.graphics.axis.polaraxes-properties.html#bu8f1sf_sep_shared-ThetaAxisUnits

[Shreen El-Sapa]

see attached file