how to find a mean across rows
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harley
am 4 Okt. 2013
Kommentiert: Image Analyst
am 5 Okt. 2013
i have a code that produces a matrix, i want it to find the mean across the rows rather than down each column. i tried the below but keep getting an error.
??? In an assignment A(I) = B, the number of elements in B and
I must be the same.
lambdaMJ = 7.2;
MJ_Flow = (30/60)*2;
A = 100;
B = 70;
C = 4;
D = B + C;
E = A - B - C;
for a = 1:5;
Num_cylces = 1;
XMJ=(poissrnd(lambdaMJ, A, Num_cylces));
lambdaMJ_sec(a) = mean(XMJ)/10;
FMJ_cars_wait = @(T11,MJ_V11) (lambdaMJ_sec(a));
[T11,MJ_V11] = ode45(FMJ_cars_wait,[0,E],MJ_Flow);
Major11(a) = mean(MJ_V11,2); %CANT GET THIS TO WORK
end
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Akzeptierte Antwort
Image Analyst
am 4 Okt. 2013
Bearbeitet: Image Analyst
am 5 Okt. 2013
What is the loop for? It's not needed. Just do this:
Major11 = mean(MJ_V11,2);
If MJ_V11 changes inside the loop, then you can still have it in the loop:
for a = 1 : 5 % No() or ; needed
MJ_V11 = whatever.....
Major11(a) = mean(MJ_V11(a,:),2);
end
Note how I added an index to Major11 so that it doesn't get overwritten every time.
8 Kommentare
Image Analyst
am 5 Okt. 2013
That's because you had
for a = 1:5
If you want all the rows, you need to go over all the rows, not just 5 of them:
[rows, columns] = size(MJ_V11);
for a = 1 : rows
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