Simple Matrix operation using for loop

Hello all, I want to do following matrix operation, I have two matrices y and errorsample as: y=y=[0.53, 0.6, 0.58, 0.68, 0.85, 0.85];1X6 matrix errorsample=normrnd(0,stdev,1,1e4);1X1e4 matrix

Now I want to create new matrix Y (1e4X6) such that Y(i)(j)=y(j)-errorsample(i)

For that I have written following code: y=[0.53, 0.6, 0.58, 0.68, 0.85, 0.85]; stdev=0.0523; errorsample=normrnd(0,stdev,1,1e4); for i=1:1:1e4; for j=1:1:6; Y(i)(j)=y(j)-errorsample(i); end end

but after running this, I am getting following error: ??? Error: File: Q4.m Line: 23 Column: 5 ()-indexing must appear last in an index expression.

Can anybody please tell me how to debug this problem, It's urgent Thanks in advance,

Nikhil

Answer 1

[Azzi Abdelmalek]

Maybe you want

y=[0.53, 0.6, 0.58, 0.68, 0.85, 0.85];
stdev=0.0523;
errorsample=normrnd(0,stdev,1,1e4);
out=zeros(1e4,6);
for i=1:1:1e4;
  for j=1:1:6;
      out(i,j)=y(j)-errorsample(i);
  end
end
disp(out)

[Nikhil]

Hey, Thanks a lot for your quick reply. My next stage is I want to perform regression analysis on each row matrix Y. And I want to store the answers of each regression analysis on matrix form. generally output of regress command is two vectors my code for this is as follows:

x=[0,0.2, 0.4, 0.6, 0.8, 1.0];
errorsample=normrnd(0,stdev,1,1e4);
for i=1:1:1e4;
  for j=1:1:6;
  Y(i,j)=y(j)-errorsample(i);
  end
end
xx=[ones(6,1),x'];
for i=1:1:1e4;
  b=regress(Y(i,:)',xx);
  Z(i)=(b);
end

The error which I am getting is as follows: ??? In an assignment A(I) = B, the number of elements in B and I must be the same.

Error in ==> Q4 at 29 Z(i)=(b);

kindly help me to debug this, Thanks in advance,

Nikhil

[Azzi Abdelmalek]

y=[0.53, 0.6, 0.58, 0.68, 0.85, 0.85];
stdev=0.0523;
errorsample=normrnd(0,stdev,1,1e4);
Y=zeros(1e4,6);
for i=1:1:1e4;
  for j=1:1:6;
 Y(i,j)=y(j)-errorsample(i);
  end
end
x=[0,0.2, 0.4, 0.6, 0.8, 1.0];
xx= [ones(6,1),x'];
Z=zeros(1e4,2);
for i=1:1:1e4;
  b=regress(Y(i,:)',xx);
  Z(i,:)=b';
end