How can I plot the SNR graph?
13 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
studentmatlaber
am 1 Aug. 2021
Kommentiert: Sulaymon Eshkabilov
am 12 Aug. 2021
Hello to everyone. I want to create a Pd - SNR dB graph. I extracted the Probability detection formula. Here I took the power of the noise as a variable to generate Snr_dB. When L=100, the graph looks good, but as I enlarge the L value, my graph gets distorted. I couldn't understand why. When L values are 10,100,1000, I expect a graph similar to the one I will put below, but it breaks down except for the value of 100. I will be glad if you can help me by sharing the code. If there is something in the code that you don't understand, I can explain.
L=100;
thr=0.01;
snr_dB = [-25:2:20]; % SNR in decibels
snr = 10.^(snr_dB./10);
for k=1:length(snr)
n_sigma(k)=(0.0206+0.0074)/snr(k);
Pd_denklem(k) = (thr-L*(0.0206+n_sigma(k)+0.0074))/sqrt((L*(4*0.0074*(0.0206+n_sigma(k))+2*(0.0206+n_sigma(k))^2)));
pd(k)=qfunc(Pd_denklem(k));
end
plot(snr_dB,pd)
4 Kommentare
Sulaymon Eshkabilov
am 2 Aug. 2021
I will try to rewrite the code according to your posted formulations.
Akzeptierte Antwort
Sulaymon Eshkabilov
am 2 Aug. 2021
I have looked through your code that is written according to your provided formulations. That means that your provided formulations are not accurate. As we know that SNR = (Power of signal)/(Power of noise) and SNR (dB) = 10*log10( (Power of signal)/(Power of noise)). Thus, my advise is to verify your formulations carefully for once more. Particularly, a first formulation SNR = (S_x^2+M_x^2)/S_w^2 = (0.0206+0.0074)/n_sigma has to be checked. Moreover, what is N in your shown reference plot. In addition, the values of lambda and L should be taken carefully.
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Annotations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!