Unable to convert expression into double array. Cannot use quiver.

3 Ansichten (letzte 30 Tage)
Tai Nguyen
Tai Nguyen am 26 Jul. 2021
Beantwortet: VBBV am 29 Mär. 2024
I know the problem is I use a variable to assign the function but I don't know how to fix.
Hope anybody can help me.
Thank a lot.
Here is my code:
clc
close all
syms x y c
k = 5;
[x,y] = meshgrid(-3:1:3);
[P] = vector_inputP();
[Q] = (vector_inputQ(k));
kt = kttruongbaotoan(P,Q);
if kt == 1
F = tinhhamthe(P,Q);
F = expand(F);
disp(F);
[P] = vector_inputP();
[Q] = (vector_inputQ(k));
quiver(x,y,P,Q);
end
%% Question A
function [kt] = kttruongbaotoan(P,Q)
syms x y
if diff(P,y)==diff(Q,x)
fprintf('*>Truong vecto F = < Q , P > = ');
disp([Q,P]);
fprintf(' la truong bao toan. Ham the F(x,y) = ');
kt=1;
else
fprintf('*>Truong vecto F = < Q , P > = ');
disp([Q,P]);
fprintf('khong la truong bao toan\n');
kt=0;
end
end
%% Question B
function [F] = tinhhamthe(P, Q)
syms x y c
F1 = expand(int( P , x));
F2 = Q - diff(F1,y);
F2 = int(F2, y);
F = F2 + F1 + c;
end
%%
function [P] = vector_inputP(k)
syms x y
if k == 5
P = 2 * x - 3 * y;
elseif k == 6
P = exp(x) * cos(y);
elseif k == 7
P = exp(x) * sin(y);
elseif k == 8
P = 3 * x^2 - 2 * y^2;
elseif k == 9
P = y * exp(x) + sin(y);
elseif k == 10
P = x * y * cos(x*y) + sin(x*y);
elseif k == 11
P = log(y)+ 2 * x * y^3;
elseif k == 12
P = x * y * cosh(x*y) + sinh(x*y);
end
end
%%
function [Q] = vector_inputQ(k)
syms x y
if k == 5
Q = - 3*x + 4*y - 8;
elseif k == 6
Q = exp(x) * sin(y);
elseif k == 7
Q = exp(x) * cos(y);
elseif k == 8
Q = 4*x*y + 3;
elseif k == 9
Q = exp(x) + x * cos(y);
elseif k == 10
Q = x^2 * cos(x*y);
elseif k == 11
Q = 3 * x^2 * y^2 + x / y;
elseif k == 12
Q = x^2 * cosh(x*y);
end
end

Antworten (1)

VBBV
VBBV am 29 Mär. 2024
@Tai Nguyen, Use a different variable name for meshgrid outputs and use subs for symbolic expressions to replace with numeric arrays
syms x y c
k = 5;
[X,Y] = meshgrid(-3:1:3); % use a different variable name for meshgrid outputs
[P] = vector_inputP(k);
[Q] = (vector_inputQ(k));
kt = kttruongbaotoan(P,Q);
*>Truong vecto F = < Q , P > =
la truong bao toan. Ham the F(x,y) =
if kt == 1
F = tinhhamthe(P,Q);
F = expand(F);
disp(F);
[P] = vector_inputP(k);
[Q] = (vector_inputQ(k));
P = double(subs(P,{x,y},{X,Y}));
Q = double(subs(Q,{x,y},{X,Y}));
quiver(X,Y,P,Q);
end
%% Question A
function [kt] = kttruongbaotoan(P,Q)
syms x y
if diff(P,y)==diff(Q,x)
fprintf('*>Truong vecto F = < Q , P > = ');
disp([Q,P]);
fprintf(' la truong bao toan. Ham the F(x,y) = ');
kt=1;
else
fprintf('*>Truong vecto F = < Q , P > = ');
disp([Q,P]);
fprintf('khong la truong bao toan\n');
kt=0;
end
end
%% Question B
function [F] = tinhhamthe(P, Q)
syms x y c
F1 = expand(int( P , x));
F2 = Q - diff(F1,y);
F2 = int(F2, y);
F = F2 + F1 + c;
end
%%
function [P] = vector_inputP(k)
syms x y
if k == 5
P = 2 * x - 3 * y;
elseif k == 6
P = exp(x) * cos(y);
elseif k == 7
P = exp(x) * sin(y);
elseif k == 8
P = 3 * x^2 - 2 * y^2;
elseif k == 9
P = y * exp(x) + sin(y);
elseif k == 10
P = x * y * cos(x*y) + sin(x*y);
elseif k == 11
P = log(y)+ 2 * x * y^3;
elseif k == 12
P = x * y * cosh(x*y) + sinh(x*y);
end
end
%%
function [Q] = vector_inputQ(k)
syms x y
if k == 5
Q = - 3*x + 4*y - 8;
elseif k == 6
Q = exp(x) * sin(y);
elseif k == 7
Q = exp(x) * cos(y);
elseif k == 8
Q = 4*x*y + 3;
elseif k == 9
Q = exp(x) + x * cos(y);
elseif k == 10
Q = x^2 * cos(x*y);
elseif k == 11
Q = 3 * x^2 * y^2 + x / y;
elseif k == 12
Q = x^2 * cosh(x*y);
end
end

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