How to fix "Error using == Arrays have incompatible sizes for this operation." in this code?

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Hi, I am writing the following code:
for k = 1 : length(theFiles) % files are alreaady defined in original code
p=1;
t=1;
for q=1:43 % there are 43 inputs for arr
c=corr2(B0,mask);
arr(p)=abs(c);
if(arr(p)<1)
if(arr(p)>0.85)
cor(t)=arr(p);
t=t+1;
end
end
p=p+1;
end %end of q loop
mx=max(cor); %conditioned arr
ixa=find(arr==mx,1) %find the location for which mx matches arr value the first instance
But when run, the result shows following:
Error using ==
Arrays have incompatible sizes for this operation.
Error in Untitled12 (line 264)
ixa=find(arr==mx,1);
It is noteworthy that, the error shows only for certain image inputs. For other inputs, the code works fine.
How can I fix it?

Akzeptierte Antwort

KSSV
KSSV am 7 Jul. 2021
Error is clear, you are trying to equate arr and mx. Check do they have same dimensions? They have different dimensions that's why error.
A = rand(2) ; B = rand(2) ;
A == B % no error as the dimensions are same
ans = 2×2 logical array
0 0 0 0
C = rand(3) ;
A == C % error as the dimensions are different
Arrays have incompatible sizes for this operation.
  6 Kommentare
Walter Roberson
Walter Roberson am 9 Feb. 2023
If you change the calls to
h11=integral(h, 0, 10, 'arrayvalued', true); %inf
h22=integral(v, 0, 10, 'arrayvalued', true);%inf
then the integrals can proceed -- but they take a long time. Long enough that I do not know yet whether the steps after that would be compatible with the values returned by those statements.
Walter Roberson
Walter Roberson am 9 Feb. 2023
psi1=psi1+(Ai.*(r.^(-i+1)+h11)+(r.^(1./2).*besselk(i-1./2,r.*alpha)+h22).*Bi).*gegenbauerC(i,-1./2, cos(t));
Variable psi1 is not defined at that point in the code. For debugging purposes we can initialize it to 0 before that line.
[DH1,hh2]=contour(x,y,psi,10,'-k');
Variable psi is not defined at that point in the code. For debugging purposes we can use psi1 instead.
psi1=psi1+(Ai.*(r.^(-i+1)+h11)+(r.^(1./2).*besselk(i-1./2,r.*alpha)+h22).*Bi).*gegenbauerC(i,-1./2, cos(t));
That comes out as all zero, because Ai and Bi are zero.

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