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How to take number between two nested cell arrays

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Ahmad Bayhaqi
Ahmad Bayhaqi am 6 Jul. 2021
Kommentiert: Chunru am 6 Jul. 2021
Hi,
I have two nested cell arrays
A = {[27,28,30,31]},{[26,25,30]},{[33,29,31,27,28]};
B = {[30,64,72,85]},{[15,33,62]},{[45,62,77,84,90]};
How can I take a max value of all entry nested in A and pick a value in B which corresponds to the max value of A?
so the result will be:
C = 33
D = 45
Thank you

Antworten (2)

KSSV
KSSV am 6 Jul. 2021
A = {[27,28,30,31],[26,25,30],[33,29,31,27,28]};
B = {[30,64,72,85],[15,33,62],[45,62,77,84,90]};
A = cell2mat(A) ;
B = cell2mat(B) ;
[val,idx] = max(A) ;
iwant = B(idx)
  2 Kommentare
Ahmad Bayhaqi
Ahmad Bayhaqi am 6 Jul. 2021
I am afraid that cell2mat doesnt work for cell.
because in A and B, I have three nested cell
A = {[27,28,30,31]},{[26,25,30]},{[33,29,31,27,28]};
B = {[30,64,72,85]},{[15,33,62]},{[45,62,77,84,90]};
so, I got this error below;
"cell2mat does not support cell arrays containing cell arrays or objects".
KSSV
KSSV am 6 Jul. 2021
Wy you want to put extra cell braces in there?

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Chunru
Chunru am 6 Jul. 2021
You can do the following (the code you gave above is NOT a nested cell):
A = {{[27,28,30,31]},{[26,25,30]},{[33,29,31,27,28]}};
B = {{[30,64,72,85]},{[15,33,62]},{[45,62,77,84,90]}};
A1= []; B1=[];
for i=1:length(A)
A1 = [A1 A{i}{1}];
B1 = [B1 B{i}{1}];
end
[C, id] = max(A1)
C = 33
id = 8
D = B1(id)
D = 45
  6 Kommentare
Ahmad Bayhaqi
Ahmad Bayhaqi am 6 Jul. 2021
I am sorry for being too much asking, but still got an error message when use that line of code.
why it's said
"Cell contents reference from a non-cell array object"
Chunru
Chunru am 6 Jul. 2021
Your data is in a mixed format. Some elements are cells and some are arrays. Some are row vector and some are column vector. This cause the problem.
The following take care of these problems:
load('A', 'A');
load('B', 'B');
A1= []; B1=[];
for i=1:length(A)
if iscell(A{i})
A1 = [A1; A{i}{1}(:)];
B1 = [B1; B{i}{1}(:)];
else
A1 = [A1; A{i}(:)];
B1 = [B1; B{i}(:)];
end
end
[C, id] = max(A1)
D = B1(id)

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