How to increase speed of this code
9 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
clc,clear,close all
format short
syms AX0
e=0.2;
OM=[1:100:20000];
ET=sqrt(-1);
A11 = 17.8*10^10;
A33 = 18.43*10^10;
A13 = 7.59*10^10;
%A56 = 1.89*10^10;
A55 = 4.357*10^10;
%A66 = 4.42*10^10;
A56=A55;
A66=A55;
AL15 = 37;
AL33 = 1.33;
AL31 = 12;
AL35 = 0.23;
GM11= 85.2;
GM33= 28.7;
RO=1.74*10^3;
NON=RO*(e^2).*(OM.^2);
NA55=A55-NON;
NA33=A33-NON;
NA11=A11-NON;
NA66=A66-NON;
AP2=NA11./NA55;
AP3=A33./NA55;
AP4=NA66./NA33;
AP44=A33./NA33;
AP24=(A13+A56);
AP25=AL15+AL31;
B1OKS=AP2-AP3*AX0;
B2OKS=AP4-AP44*AX0;
B3OKS=GM11/(AL33*AL33-GM33);
B1OK=sqrt(B1OKS);
B2OK=sqrt(B2OKS);
B3OK=sqrt(B3OKS);
APT1=AL15-AL33.*B1OKS;
APT2=AL15-AL33.*B2OKS;
APT3=AL15-AL33.*B3OKS;
AZT1=ET*AP25*B1OK./APT1;
AZT2=ET*AP25*B2OK./APT2;
AZT3=ET*AP25*B3OK./APT3;
AXT1=AP24.*AZT1./AP25;
AXT2=AP24.*AZT2./AP25;
AXT3=AP24.*AZT3./AP25;
A1=ET*A13-B1OK.*AZT1*A33-ET*AXT1*AL35+B1OK.*AXT1*AL33;
A2=ET*A13-B2OK.*AZT2*A33-ET*AXT2*AL35+B2OK.*AXT2*AL33;
A3=ET*A13-B3OK.*AZT3*A33-ET*AXT3*AL35+B3OK.*AXT3*AL33;
B1=ET*AZT1*A56-B1OK*A55-ET*AL31*AXT1+B1OK.*AXT1*AL35;
B2=ET*AZT2*A56-B2OK*A55-ET*AL31*AXT2+B2OK.*AXT2*AL35;
B3=ET*AZT3*A56-B3OK*A55-ET*AL31*AXT3+B3OK.*AXT3*AL35;
% CHARGE FREE
C1=ET*AL15-B1OK.*AZT1*AL33-B1OK.*AXT1*GM33;
C2=ET*AL15-B2OK.*AZT2*AL33-B2OK.*AXT2*GM33;
C3=ET*AL15-B3OK.*AZT3*AL33-B3OK.*AXT3*GM33;
AU= A1.*B2.*C3-A1.*B3.*C2-A2.*B1.*C3+A2.*B3.*C1+A3.*B1.*C2-A3.*B2.*C1;
W =[];
for i=1:numel(OM)
AUU=AU(:,i);
r= double(solve(AUU==0,AX0));
r1=(sqrt((A33*r)./RO));
W = [W,r1];
end
SP1=W(1,:);
SP2=W(2,:);
SP3=W(3,:);
SP4=W(4,:);
How I increase speed of runing of above code. It takes long time to run .
0 Kommentare
Antworten (3)
Yongjian Feng
am 3 Jul. 2021
Hello Asha,
matlab provides profile for this purpose. (https://www.mathworks.com/help/matlab/ref/profile.html).
Try it please.
Thanks,
Yongjian
Heran Wang
am 3 Jul. 2021
I recommend the higher version of MATLAB.
The higher the vesion is, the faster the caculation will be.
For example, the MATLAB 2021a will two times faster than MATLAB 2017b.
Try it ~
0 Kommentare
VBBV
am 12 Feb. 2025 um 1:12
@ASHA RANI one way to speed up code is increase the step size or increment in the OM array. The variables used in the equations to solve them also contain big numbers which can consume more memory during execution. You could also vectorize the for loop if needed.
clc,clear,close all
format short
tic
syms AX0
e=0.2;
OM=[1:500:20000]; % change the step or increment in this array
%^^^^
ET=sqrt(-1);
A11 = 17.8*10^10;
A33 = 18.43*10^10;
A13 = 7.59*10^10;
%A56 = 1.89*10^10;
A55 = 4.357*10^10;
%A66 = 4.42*10^10;
A56=A55;
A66=A55;
AL15 = 37;
AL33 = 1.33;
AL31 = 12;
AL35 = 0.23;
GM11= 85.2;
GM33= 28.7;
RO=1.74*10^3;
NON=RO*(e^2).*(OM.^2);
NA55=A55-NON;
NA33=A33-NON;
NA11=A11-NON;
NA66=A66-NON;
AP2=NA11./NA55;
AP3=A33./NA55;
AP4=NA66./NA33;
AP44=A33./NA33;
AP24=(A13+A56);
AP25=AL15+AL31;
B1OKS=AP2-AP3*AX0;
B2OKS=AP4-AP44*AX0;
B3OKS=GM11/(AL33*AL33-GM33);
B1OK=sqrt(B1OKS);
B2OK=sqrt(B2OKS);
B3OK=sqrt(B3OKS);
APT1=AL15-AL33.*B1OKS;
APT2=AL15-AL33.*B2OKS;
APT3=AL15-AL33.*B3OKS;
AZT1=ET*AP25*B1OK./APT1;
AZT2=ET*AP25*B2OK./APT2;
AZT3=ET*AP25*B3OK./APT3;
AXT1=AP24.*AZT1./AP25;
AXT2=AP24.*AZT2./AP25;
AXT3=AP24.*AZT3./AP25;
A1=ET*A13-B1OK.*AZT1*A33-ET*AXT1*AL35+B1OK.*AXT1*AL33;
A2=ET*A13-B2OK.*AZT2*A33-ET*AXT2*AL35+B2OK.*AXT2*AL33;
A3=ET*A13-B3OK.*AZT3*A33-ET*AXT3*AL35+B3OK.*AXT3*AL33;
B1=ET*AZT1*A56-B1OK*A55-ET*AL31*AXT1+B1OK.*AXT1*AL35;
B2=ET*AZT2*A56-B2OK*A55-ET*AL31*AXT2+B2OK.*AXT2*AL35;
B3=ET*AZT3*A56-B3OK*A55-ET*AL31*AXT3+B3OK.*AXT3*AL35;
% CHARGE FREE
C1=ET*AL15-B1OK.*AZT1*AL33-B1OK.*AXT1*GM33;
C2=ET*AL15-B2OK.*AZT2*AL33-B2OK.*AXT2*GM33;
C3=ET*AL15-B3OK.*AZT3*AL33-B3OK.*AXT3*GM33;
AU= A1.*B2.*C3-A1.*B3.*C2-A2.*B1.*C3+A2.*B3.*C1+A3.*B1.*C2-A3.*B2.*C1;
W =[];
for i=1:numel(OM)
AUU=AU(:,i);
r= double(solve(AUU==0,AX0));
r1=(sqrt((A33*r)./RO));
W = [W,r1];
end
SP1=W(1,:);
SP2=W(2,:);
SP3=W(3,:);
SP4=W(4,:);
toc
0 Kommentare
Siehe auch
Kategorien
Mehr zu Get Started with MATLAB finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!