Solve equation with 2 unknowns using solve
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Jane Low
am 30 Jun. 2021
Kommentiert: Jane Low
am 30 Jun. 2021
How to solve the two equation below?
cos(3a)+cos(3b)=0
cos(a)+cos(b)=1.6
Ans:
a = 7.6 degree = 0.132645 rad
b = 52.4 degree = 0.9145525 rad
Hereby my code
syms a b
sol = solve(cos(3*a)+cos(3*b)==0, cos(a)+cos(b)==1.6,[a,b])
sol.a
sol.b
and it gave me this
In sym/solve>warnIfParams (line 478)
In sym/solve (line 357)
sol =
struct with fields:
a: [1×1 sym]
b: [1×1 sym]
ans =
z
ans =
z1
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Akzeptierte Antwort
Walter Roberson
am 30 Jun. 2021
syms a b
sol = vpasolve(cos(3*a)+cos(3*b)==0, cos(a)+cos(b)==1.6,[a,b],[0, pi; 0, pi])
sol.a
sol.b
Your equations are symmetric in your variables, so this is an equivalent solution to what you posted.
Weitere Antworten (1)
Alan Stevens
am 30 Jun. 2021
There are an infinite number of solutions! Restrict the range. One possibility is as follows
bfn = @(a) acos(1.6-cos(a));
fn = @(a) cos(3*a)+cos(3*bfn(a));
a0 = 0.1; % initial guess
a = fzero(fn, a0);
b = bfn(a);
disp([a, b])
disp(rad2deg([a,b]))
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