How to build ratio between two columns of a matrix?
10 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I have a matrix of size 102 x 2555 I want to select each column from 1 to 2555 of this matrix and then divide to each column of this matrix. For example: I have matrix
A=
1 2 3 4 5 6
2 3 4 5 6 7
3 4 5 6 4 6
5 6 8 7 1 3
I want to build the ratios like this:
ratio1=column1./each column in matrix A
ratio2=column2./each column in matrix A
ratio3=column3./each column in matrix A
....
ratio6=column6./each column in matrix A
Thanks for your help!
0 Kommentare
Akzeptierte Antwort
the cyclist
am 10 Sep. 2013
A= ...
[1 2 3 4 5 6; ...
2 3 4 5 6 7; ...
3 4 5 6 4 6; ...
5 6 8 7 1 3];
[nrow,ncol] = size(A);
for n = 1:ncol
ratio{n} = bsxfun(@rdivide,A(:,n),A)
end
4 Kommentare
Jan
am 10 Sep. 2013
Bearbeitet: Jan
am 10 Sep. 2013
@Viet Duc: As result you get 2555 matrices of type double with 102*2555 elements, which occupy about 5.32 GB. With a 16 GB machine and a 64 bit system, this is no problem, but it fails for a 32 bit machine.
Do you really need such a large pile of data simultaneously in the memory?
Andrei Bobrov
am 10 Sep. 2013
num2cell(bsxfun(@rdivide,permute(A,[1 3 2]),A),[1 2])
Weitere Antworten (1)
Siehe auch
Kategorien
Mehr zu Numeric Types finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!