Loop and Conditional Statements
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Paulo Eduardo Beiral
am 24 Jun. 2021
Kommentiert: Paulo Eduardo Beiral
am 24 Jun. 2021
I've got two vectors 1x366 u and v, and I have to make a new 1x366 vector of the arctg of u and v.
But I've got a few conditions depending if the respective value of u and v are negative or positive.
Here's some of the code which I started writing, but I am stuck.
Thank you for any help.
for n = 1:length(u)
if u(n) <0 && v(n) < 0
atan(v./u);
elseif u(n) > 0 && v(n) < 0
atan(u./v) + 4.712;
elseif u(n) < 0 && v(n) > 0
atan(u./v) + 1.571;
elseif u(n) > 0 && v(n) > 0
atan(v./u) + 3.142;
end
end
2 Kommentare
Scott MacKenzie
am 24 Jun. 2021
Have you looked at atan2? This is the four-quadrant version of atan -- might be what you need.
Akzeptierte Antwort
Steven Lord
am 24 Jun. 2021
As written your code calls atan at most once per element of u but then throws that result away. You also have magic numbers that look like approximations to multiples of pi.
Instead I recommend using logical indexing.
base1 = atan(v./u);
base2 = atan(u./v);
result = NaN(size(u)); % determine what you want result to be if none of the cases hold
case1 = (u < 0) & (v < 0);
result(case1) = base1(case1);
case2 = (u > 0) & (v < 0);
result(case2) = base2(case2) + (3*pi/2);
% and similar for case3 and case4
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!