I want to ask what wrong with my codes . please help me out

% Power Method Algorithm

n=input('Enter dimension of the matrix, n: ');
A = zeros(n,n);
x = zeros(1,n);
y = zeros(1,n);
tol = input('Enter the tolerance, tol: ');
m = input('Enter maximum number of iteration, m: ');


A=[0.000251 0.000163 ; 0.000251 0.0003261];
x=[-2.1; 0.9];


k = 1; 1p = 1;
amax = abs (x(1));
for i = 2 : n
    if abs(x(i)) > amaz
        amax = abs(x(i));
        1p = i;
    end 
end
for i = 1 : n
    x(i) = x(i)/max;
end

fprintf('\n\n  Ite.    Eigenvalue..........Eigenvectores..........\n');
while k <= m
    for i = 1 : n
        y(i) = 0;
        for j = 1 : n
            y(i) = y(i) + A(i,j) * x(j);
        end
    end
    ymu = y(1x);
    1p = 1;
    amax = abs(y(1));
    for i = 2 : n
        if abs(y(i)) > amax 
            amax = abs(y(i));
            1p = i;
        end
    end
    if amax <= 0
        fprintf('0 eigenvalue - select another ');
        fprint('initial vector and begin again\n');
    else
        err = 0;
        for i = 1 : n
            t = y(i)/y(1p);
            if abs(x(i)-t) > err
                err = abs(x(i)-t);
            end
            x(i) = t;
        end
        fprintf('%4d    %11.8f' , k, ymu);
        for i = 1 : n
            fprintf('  %11.8f', x(i));
        end
        fprintf('\n');
        if err <= tol
            fprintf('\n\nThe eigenvalue after %d iterations is: %11.8f \n',k, ymu);
            fprintf('The corresponding eigenvector is: \n');
            for i = 1 ; n
                fprintf('                    %11.8f\n', x(i));
            end
            fprintf ('\n');
            break
        end
        k= k+1;
    end
end
if k > m
fprintf ('Method did not coverge within %d iteration\n', m);
end

the error :

File: power_method.m Line: 15 Column: 9

Invalid expression. Check for missing multiplication operator, missing or unbalanced

delimiters, or other syntax error. To construct matrices, use brackets instead of parentheses.

Answer 1

[KSSV]

You should not name a variable starting with a number. Variable name should start with a character.

Replace the variable

1p = 1 ;

with

p1 = 1 ; 

[JALALUDIN ARIS]

thanks sir

Answer 2

[Walter Roberson]

1p is not a valid variable name in MATLAB. There are not many computer languages in which it would be considered a valid variable name without some special marking (for example in Maple it could be a valid variable name if you marked it as `1p`). The last computer language that I saw that permitted such variable names without special distinction was Algol 68.

[JALALUDIN ARIS]

thanks a lot