MEX memory leak - is this a bug?
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Ayal
am 2 Sep. 2013
Kommentiert: Mateusz Pieniak
am 3 Mai 2017
I tried reporting this as a bug, with no response so far. Before I try a little harder, I want to make sure this is indeed a bug. I asked a few people, here & other places, and no one can explain this:
mxGPUArray * tmp=mxGPUCopyFromMxArray(prhs[0]);
plhs[0]=mxGPUCreateMxArrayOnGPU(tmp);
mxGPUDestroyGPUArray(out);
This code causes memory leaks (at least in Matlab 2013a, compiled with Visual Studio 2010). I run the following on loop in matlab:
foo=gpuArray.randn(1000);
res=MyMex(foo);
gpuDevice
And I see that with every iteration, there is less free memory in the GPU device. Correct me if i'm wrong, but this SHOULD NOT be happening. Matlab should free the values previously stored by "res", but It doesn't seem to.
NOTE: This is not bug 954239.
I've been working on this problem for two weeks, with no luck. There's always some memory leak. Does anyone have any idea what's going on? Did I miss something?
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Edric Ellis
am 4 Sep. 2013
It appears as though there's a problem with mxGPUCopyFromMxArray. Please could you try the following workaround:
/**
* Replacement for mxGPUCopyFromMxArray
*/
mxGPUArray * mxGPUCopyFromMxArray2(mxArray const * mx) {
if (mxIsGPUArray(mx)) {
mxGPUArray const * tmp = mxGPUCreateFromMxArray(mx);
mxGPUArray * returnValue = mxGPUCopyGPUArray(tmp);
mxGPUDestroyGPUArray(tmp);
return returnValue;
} else {
return const_cast<mxGPUArray *>(mxGPUCreateFromMxArray(mx));
}
}
4 Kommentare
Edric Ellis
am 9 Sep. 2013
It's possible that the remaining memory usage behaviour might simply be artefacts of the allocation pooling.
Weitere Antworten (1)
Edric Ellis
am 3 Sep. 2013
I think this is nothing to do with the MEX interface, and instead to do with the way MATLAB tries to recycle memory allocations on the device, as demonstrated by the following example:
% First, check the free memory on the device
>> dev = gpuDevice(); dev.FreeMemory
ans =
5.5265e+09
% Next, make 100 allocations of 8MB
>> for idx = 1:100, c{idx} = gpuArray.ones(1000); end
>> dev.FreeMemory
ans =
4.7138e+09
% Now, clear all but one of those and check the free memory
>> c(2:end) = [];
>> dev.FreeMemory
ans =
4.7138e+09
% Clear all arrays, and check free memory again
>> clear c
>> dev.FreeMemory
ans =
5.5265e+09
You can see here that freeing some arrays doesn't change the amount of free memory on the device, but when all arrays have been freed then all the memory is returned.
6 Kommentare
Mateusz Pieniak
am 3 Mai 2017
I have the same issue. Did anybody resolved it? It was 3rd September 2013 and a few years passed...
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