Create a matrix out of single values if a for loop?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello,
is it possible to create a 1xF matrix in a for loop out of single values?
n = 2;
r = 0.5;
a = 10;
b = 5;
p = [r + (a-2*r)*rand(n,1),r + (b-2*r)*rand(n,1 )];
for i = 1:n
for j = i:n
if i == j
continue
end
H = (norm(p(i,:)-p(j,:))<=2*r)
end
end
5 Kommentare
SungJun Cho
am 17 Jun. 2021
You should preallocate H as a matrix and save each values into your matrix. For example,
% ...
H = zeros(n,n);
for i = 1:n
for j = i:n
% ...
H(i,j) = (norm(p(i,:)-p(j,:))<=2*r)
end
end
Akzeptierte Antwort
KSSV
am 17 Jun. 2021
r = 0.5; a = 0; b = 5;
n = 3 ;
p=[r + (a-2*r)*rand(n,1),r + (b-2*r)*rand(n,1)];
H = zeros(1,[]) ;
count = 0 ;
for i = 1:n
for j = i:n
if i == j
continue
end
count = count+1 ;
H(1,count) = (norm(p(i,:)-p(j,:)))
end
end
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!