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How can I integral this equation and plot? please help me

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jameslk
jameslk am 16 Jun. 2021
Kommentiert: jameslk am 16 Jun. 2021
dy/dt = y*t^2 + 3*y
y(0) = 1
t= 0:2
This is the equation which I want to integral
But when I integrate and plot this how can I get dy/dt. Because dy/dt becomes y when i intergrate it.
  2 Kommentare
John D'Errico
John D'Errico am 16 Jun. 2021
You want to plot the derivative?
Surely it would be true, that if you know y(t), and t, then you can compute dy/dt, since you have the expression right there.
jameslk
jameslk am 16 Jun. 2021
yes i want to plot that equation after integral
and how can i get integral constant?
I don't have idea to do this with function int or integral

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Walter Roberson
Walter Roberson am 16 Jun. 2021
syms y(t) c
eqn = diff(y) == y*t^2 + 3*y
eqn(t) = 
ic = y(0) == 1
ic = 
sol = dsolve([eqn, ic])
sol = 
fplot(sol, [0 2])

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