Trouble getting data outside of parfor loop

3 Ansichten (letzte 30 Tage)
John Doe
John Doe am 27 Aug. 2013
Beantwortet: John Doe am 28 Okt. 2013
Hello, I have a process that needs to be applied to a 90 trials of an 11 electrode signal. The result of each trial is in the form of 11 different matrices of a number of rows that varies between trials (no greater than 12). I'm having trouble getting those matrices stored without matlab saying it can't be done whilst using parfor.
I create giant matrices of zeros outside the loop that has enough space for the max possible number of rows. Then inside the loop I try and pass the data to giantmatrix(rowNumber:rowNumber + row length of data, :).
clear all
matlabpool;
load MIdata25;
fs = 160;
numberElectrodes = 11;
Left1 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left2 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left3 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left4 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left5 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left6 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left7 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left8 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left9 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left10 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
Left11 = zeros(15*length(squeeze(thinkLeft(1, :, 1))), 1312);
parfor currentTrial = 1:length(squeeze(thinkLeft(1, :, 1)))
currentTrial
chanNum = 0;
signalL=[];
signalTotal=[];
for currentElectrode = [2 6 8 9 11 13 14 16 20 41 42]
%matrix indexing stuff
signalTotal = [signalTotal; signalL3'];
end
x = %process applied to signalTotal
for currentElectrode = 1:11
xxl = zeros(numberElectrodes, length(signalL(1, :)));
for imfNo = 1:length(squeeze(x(1, :, 1)))
%matrix re-indexing stuff
end
if currentElectrode == 1
Left1(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 2
Left2(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 3
Left3(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 4
Left4(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 5
Left5(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 6
Left6(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 7
Left7(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 8
Left8(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 9
Left9(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 10
Left10(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
elseif currentElectrode == 11
Left11(((currentTrial-1)*15)+1:((currentTrial-1)*15)+length(xxl(:, 1)), :) = xxl;
end
end
midpointL(currentTrial, :) = length(xxl(:, 1));
end
With matlab showing problems with Left1-9, though it seems fine with midpointL.
  1 Kommentar
Walter Roberson
Walter Roberson am 27 Aug. 2013
Try replacing the length(xx1(:,1)) with numberElectrodes since you built xx1 with numberElectrodes as the first dimension.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

John Doe
John Doe am 28 Okt. 2013
The answer to this was that matlab does not like "parfor variable +/- integer" as it thinks it'll be used to reference a previous loop which it can't do in parallel. In this case it's the variable CurrentTrial. Creating a 3d matrix instead of a 2d one with CurrentTrial used to define the first column solved it.

Weitere Antworten (1)

Matt J
Matt J am 27 Aug. 2013
Bearbeitet: Matt J am 28 Aug. 2013
I create giant matrices of zeros outside the loop that has enough space for the max possible number of rows. Then inside the loop I try and pass the data to giantmatrix.
A better idea would probably be to dispense with Left1...9 and instead store the results (of different sizes) in a 90x11 cell array. Then combine them after the loops end as needed.
N=length(squeeze(thinkLeft(1, :, 1)));
LoopData=cell(N, 11);
parfor currentTrial = 1:N
for currentElectrode = 1:11
xxl = ...;
LoopData{currentTrial,currentElectrode}=xxl;
end
end
Now you can combine all the different xxl in LoopData using cell2mat() or similar...

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by