curve fit the function

12 Ansichten (letzte 30 Tage)
Tawhid Pranto
Tawhid Pranto am 15 Jun. 2021
Bearbeitet: dpb am 15 Jun. 2021
I am trying to curve fit the following equation with parameters d, D, Ar, Tr each of them bounded in some range. The physical constants are: gamma = 26.76E7, n = 6.59E28, Ad = 2.099E-20
The equation is broken into several parts -
w1=2*pi*x
z1=(2*w1*d^2/D)^0.5
w2=2*w1
z2=(2*w2*d^2/D)^0.5
J1=((1+5*z1/8+z1^2/8)/(1+z1+z1^2/2+z1^3/6+z1^5/81+z1^6/648))
J2=((1+5*z2/8+z2^2/8)/(1+z2+z2^2/2+z2^3/6+z2^5/81+z2^6/648))
R1_diff = Ad*(J1+4*J2)/(d*D)
R1_rot = Ar*(Tr/(1+w1^2*Tr^2)+4*Tr/(1+(w2)^2*Tr^2))
R1_IL = R1_diff + R1_rot
finally
return R1_IL
#Experimental x and y data points
xData = [2.00E+07,1.42E+07,1.01E+07,7.16E+06,5.09E+06,3.61E+06,2.57E+06,1.82E+06, ...
1.29E+06,9.20E+05,6.53E+05,4.63E+05,3.29E+05,2.34E+05,1.66E+05,1.18E+05, ...
8.39E+04,5.96E+04,4.24E+04,3.00E+04];
yData = [1.90E+01,2.11E+01,2.38E+01,2.66E+01,2.97E+01,3.26E+01,3.46E+01,3.70E+01, ...
3.84E+01,4.00E+01,4.12E+01,4.22E+01,4.33E+01,4.39E+01,4.48E+01,4.54E+01, ...
4.65E+01,4.64E+01,4.67E+01,4.67E+01];
and the bound parameters are
d = [2.00E-10, 3.5E-10], D = [3.0E-12, 4.00E-12], Ar = [3.00E9, 3.8E9], Tr = [5.00E-19, 6.9E-10]ll
I need to get the parameter values that will minimize the function and curve fit the plot of R1 vs x in loglog scale.
  1 Kommentar
dpb
dpb am 15 Jun. 2021
Bearbeitet: dpb am 15 Jun. 2021
Reformatted Q? data/code so somebody can download easily -- dpb

Melden Sie sich an, um zu kommentieren.

Antworten (0)

Kategorien

Mehr zu Linear and Nonlinear Regression finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by