Can't get string to datetime conversion to work

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Nathan Heller
Nathan Heller am 11 Jun. 2021
Kommentiert: Nathan Heller am 12 Jun. 2021
There seems to be some sort of inconsistency in the converting to datetime code I missed.
q=datetime('2017-05-17 19:36:00', 'InputFormat','yyyy-MM-dd HH:mm:ss')
this works just fine. However, when I am reading the input string '2017-05-17T19:36:00' from an array, stripping the T, and putting it in exactly the same, it fails to work. example:
%data{1}(n) has the string '2019-05-17T19:36:00'
b = strrep(data{1}(n),'T',' ');
disp(b);
%displaying displays 2017-05-17 19:36:00, just like the earlier statement
timestamp = datetime(b,'InputFormat',format);
When I do this, the error message:
Unable to convert '2017-05-17 19:36:00' to datetime using the format 'yyyy-MM-dd HH:mm:ss'.
is displayed. Am i missing something? are these not exactly the same? Thanks for your help.
  2 Kommentare
Walter Roberson
Walter Roberson am 11 Jun. 2021
could you attach data{1} as a mat file so we can check for odd characters?

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Akzeptierte Antwort

Walter Roberson
Walter Roberson am 11 Jun. 2021
The very first entry in your data{1} has a leading U+FEFF character, which is a unicode Byte Order Mark character, but is to be interpreted as a Zero-Width Non-Breaking Space if it occurs anywhere other than the first position
  3 Kommentare
Walter Roberson
Walter Roberson am 12 Jun. 2021
It probably only occurs once, but to be sure, use another strrep to replace char(65279) with empty
Nathan Heller
Nathan Heller am 12 Jun. 2021
Thanks for all your help!

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Weitere Antworten (1)

J. Alex Lee
J. Alex Lee am 11 Jun. 2021
str = '2019-05-17T19:36:00';
fmt = 'yyyy-MM-dd HH:mm:ss';
b = strrep(str,'T',' ');
disp(b);
2019-05-17 19:36:00
timestamp = datetime(b,'InputFormat',fmt)
timestamp = datetime
17-May-2019 19:36:00
Works for me ?
  1 Kommentar
Nathan Heller
Nathan Heller am 11 Jun. 2021
I still get the same error when i use your code with str = data {1}(n), so i assume there must be some problem with the data file?

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