Find the indices of the imaginary element of the matrix
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Hassan Alkomy
am 8 Jun. 2021
Beantwortet: Hassan Alkomy
am 8 Jun. 2021
Suppose I have a Matrix like this:
A=[1 2 3;
4+i 5 6-i;
7 8+i 9]
Now, I want to know if there is a way to find the indecies of the imaginary elements (by this I mean the complex numbers which have imaginary part). I am looking for an answer like that:
A(2,1)
A(2,3)
A(3,2)
or any other form the conveys the indecies information of the imaginary elements.
Thank you so much.
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Joseph Cheng
am 8 Jun. 2021
you can do a comparison to the real(A) like
A=[1 2 3;
4+i 5 6-i;
7 8+i 9]
[row col]=find(A~=real(A))
then with find you can get the row and column index values of the as real(A)~=A
Scott MacKenzie
am 8 Jun. 2021
% test matrix
A=[1 2 3;
4+i 5 6-i;
7 8+i 9]
% identify imaginary elements in A (+1 or -1)
B = imag(A)
% generate column vector of indices of imaginary elements in A
find(B~=0)
Output:
A =
1 + 0i 2 + 0i 3 + 0i
4 + 1i 5 + 0i 6 - 1i
7 + 0i 8 + 1i 9 + 0i
B =
0 0 0
1 0 -1
0 1 0
ans =
2
6
8
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