sum of array by specific index value
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Khairul Nur
am 29 Mai 2021
Bearbeitet: KALYAN ACHARJYA
am 29 Mai 2021
hi, i have two array. First array containing index and second array (hasil_tambah_array) containing the value to be sum-up as below:
index =
4
2
4
hasil_tambah_array =
3.6881
0.8506
0.0132
0.8506
10.5147
12.5147
14.5074
21.8003
11.2145
18.5074
I try to sum the second array as per index such as 3.6881,0.8506,0.0132 and 0.8506 (since the 1st index is 4) will be sum together . Then 10.5147 and 12.5147 (since the 2nd index is 2) will be sum up and respectively (next will be the rest since the index is 4).
Appreciate ur time to solve this. TQIA.
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Akzeptierte Antwort
DGM
am 29 Mai 2021
Bearbeitet: DGM
am 29 Mai 2021
This is one way. It's probably not the most efficient way, but it does the job.
idx = [4 2 4];
H = [3.6881 0.8506 0.0132 0.8506 10.5147 12.5147 14.5074 21.8003 11.2145 18.5074].';
S = cellfun(@sum,mat2cell(H,idx,1))
Bear in mind that using mat2cell() to subdivide the main vector requires that sum(idx) = numel(H), so watch out for that.
Weitere Antworten (1)
KALYAN ACHARJYA
am 29 Mai 2021
Bearbeitet: KALYAN ACHARJYA
am 29 Mai 2021
result=sum(second_arary(first_array))
More
result=sum(hasil_tambah_array(index))
2 Kommentare
KALYAN ACHARJYA
am 29 Mai 2021
Bearbeitet: KALYAN ACHARJYA
am 29 Mai 2021
index =[4
2
4];
hasil_tambah_array =[3.6881
0.8506
0.0132
0.8506
10.5147
12.5147
14.5074
21.8003
11.2145
18.5074];
result=sum(hasil_tambah_array(index))
Output:
result =
2.5518
More: Same as
>> 0.8506+0.8506+0.8506
ans =
2.5518
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