Issue with sine graph

2 Ansichten (letzte 30 Tage)
Kaylee Chavez
Kaylee Chavez am 22 Mai 2021
Kommentiert: DGM am 23 Mai 2021
I am having some difficulty graphing a function using sine. I graph it and it is either a y =x type graph or just lines. If someone could provide some direction that would be great.
%Oblique Balance Script
figure('Name','Team A Graphs');
clf;
%%Weight Ratio
subplot(2,1,1)
t=[0:0.01:180]
r = sind(30 + t) ./ sind(30 - t);
plot(t, r);
area(t,r,'FaceColor',[.8,.9,1.0]);
%Weight Graph
title('Weight ratio')
xlabel('Angle change')
ylabel('Ratio')

Antworten (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov am 22 Mai 2021
Hi,
If you're trying to plot the weight ratio explained in your previous post, that has to be up to 30 degrees.
Thus, you'd need to make some corrections in your code while selecting the range t values, e.g.:
...
t=0:.25:29;
...
Note that at t=30, y goes to inf.
Good luck.
  1 Kommentar
DGM
DGM am 23 Mai 2021
For emphasis:
t=[0:0.01:180];
r = sind(30 + t) ./ sind(30 - t); % the denominator goes to zero.
plot(t, r);
area(t,r,'FaceColor',[.8,.9,1.0]);
ylim([-100 100]) % so explicitly limit y limits
I have no idea what this plot means conceptually, but that's why it looks like it does.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Graph and Network Algorithms finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by