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How to use variable value as an input to the function?

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Marcin
Marcin on 31 Jul 2013
I have the function which takes two arguments:
match(template1 , template2);
I want to save the first and second argument name as a string:
name1 = 'template1'; name2 = 'template2';
And then pass this names into my match function:
match( name1 , name2 )
MATLAB reads it as strings but I want it to be pointers to to template1 and template2. Do you know how to achieve this?

  2 Comments

dpb
dpb on 31 Jul 2013
Better back up and describe what end objective is--Matlab is not C so talking about pointers is generally an attempt to implement something as if it were.
Marcin
Marcin on 1 Aug 2013
I'm sorry, the thing is that I have 100 templates and I need to compare them to each other by the function match, doing this manually would be 10000 lines of code, is it possible to write for loop to produce the results:
result(n)(m) = match( template(n) , template(m) )
where m and n are variables.

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Answers (2)

Walter Roberson
Walter Roberson on 31 Jul 2013
function r = match(t1 , t2)
name1 = inputname(1);
name2 = inputname(2);
r = match_by_name(name1, name2);
end
where match_by_name is your second "match" function.

  1 Comment

Walter Roberson
Walter Roberson on 1 Aug 2013
nT = length(template);
result = cell(nT,nT);
for K = 1 : nT
result{K,K} = match(template{K}, template{K}); %match against self??
for L = K + 1, nT
result{K, L} = match(template{K}, template{L});
end
end

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Richard Brown
Richard Brown on 31 Jul 2013
You can very probably get away with just passing template1 and template2 themselves (not trying to create references to them).
Matlab won't create copies unless you modify them within your match function.

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