Filter löschen
Filter löschen

how to solve this nonlinear equation?

2 Ansichten (letzte 30 Tage)
Pritha
Pritha am 21 Mai 2021
Bearbeitet: Torsten am 22 Mai 2021
m = 4.7542;
gsms = 12.684 ;
m1 = (m - gss);
p = 0.1 : 0.5 : 10 ;
k = (3 * p * pi^2 / 2)^(1/3) ;
k1 = sqrt(k^2 + m1^2);
F = (gsms * m1 * (k1 - m1^2/2 *log((k1+k)/m1))/pi^2 )-gss ;
  2 Kommentare
Tayyab Khalil
Tayyab Khalil am 21 Mai 2021
Can you clearly desribe which equation you want to solve and for which variable?
Dyuman Joshi
Dyuman Joshi am 21 Mai 2021
What is gss?
Also, you have defined k and k1 incorrectly, use elementwise operators (.*)

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Torsten
Torsten am 21 Mai 2021
Bearbeitet: Torsten am 22 Mai 2021
function main
p=0.1:0.5:10;
gss0 = 1.0;
for i=1:numel(p)
gss(i)= fzero(@(x)fun(x,p(i)),gss0)
gss0 = gss(i);
end
plot(p,gss)
end
function gssres = fun(gss,p)
m = 4.7542;
gsms = 12.684;
m1 = m - gss;
k = (3*p*pi^2 / 2)^(1/3);
k1 = sqrt(k^2+m1^2);
F = gsms*m1*( k1-m1^2/2*log((k1+k)/m1) )/pi^2 - gss
gssres = F ;
end
Maybe you will have to change gss0 = 1.0 (a guess for gss for p=0.1) to make the program start.

Weitere Antworten (1)

Mike Mierlo van
Mike Mierlo van am 21 Mai 2021
Please specify variable: 'gss'. This one is unknown in your function.
Also what Tayyab says: what do you want to solve?
It helps a lot if you comment with % after each line what the variable means.

Kategorien

Mehr zu Least Squares finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by