- https://www.mathworks.com/help/phased/ref/phased.ula-system-object.html
- https://www.mathworks.com/help/phased/ref/phased.steeringvector-system-object.html
Rotation of polar beam pattern using ULA.
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Hi,
I would like to steer the beam pattern of a ULA so its at -25° and 25°.
My code is shown below:
c = 3e8;
fc = 2e9;
lambda = c/fc;
NoOfTxAntenna = 4;
txarray = phased.ULA('NumElements',NoOfTxAntenna,'ElementSpacing',lambda/2);
steer_ang = [25;0];
stv = phased.SteeringVector('SensorArray',txarray);
w = stv(fc,steer_ang);
figure,
pattern(txarray,fc,[-180:180],0,...
'PropagationSpeed',c,...
'CoordinateSystem','polar',...
'Type','powerdb', ...
'Weights',w)
Currently the beam pattern is as shown below.
Many thanks
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Antworten (1)
Suraj Kumar
am 9 Aug. 2024
Hi Zain,
To steer the beam pattern of a Uniform Linear Array (ULA) to 25° and -25°, go through the following steps:
1. Define the required parameters and create a Uniform Linear Array using the “phased.ULA” function.
c = 3e8;
fc = 2e9;
lambda = c/fc;
NoOfTxAntenna = 4;
txarray = phased.ULA('NumElements',NoOfTxAntenna, 'ElementSpacing', lambda/2);
2. Initialize the steering angles for both directions allowing the beam pattern to rotate accordingly.
% Initialize steering angles
steer_ang1 = [25; 0];
steer_ang2 = [-25; 0];
3. Create a steering vector object using the “phased.SteeringVector” function and compute the weights for the ULA.
stv = phased.SteeringVector('SensorArray', txarray);
w1 = stv(fc, steer_ang1);
w2 = stv(fc, steer_ang2);
4. Plot the beam pattern for both the steering angles.
figure;
pattern(txarray, fc, [-180:180], 0, ...
'PropagationSpeed', c, ...
'CoordinateSystem', 'polar', ...
'Type', 'powerdb', ...
'Weights', w1);
figure;
pattern(txarray, fc, [-180:180], 0, ...
'PropagationSpeed', c, ...
'CoordinateSystem', 'polar', ...
'Type', 'powerdb', ...
'Weights', w2);
You can look at the output below for a better understanding:
To know more about “phased.ULA” and “phased.SteeringVector” functions, please go through the documentation below:
Hope this works for you!
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