how to use fsolve in for loop?

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Luqman Alabri
Luqman Alabri am 20 Mai 2021
Kommentiert: Luqman Alabri am 21 Mai 2021
I need to pass different values of (theta_r) into F(1) and F(2) to get different values of x(1) and x(2).
i use this code, but it shows me many errors.
clear all;
%defining the parameters.
global R L3 L4 L5 theta_r
R=80; L5=360; L4=360; L3=120; n=2; m=100*n;
theta_r=linspace(0,2*pi*n,m);
function F = value(x,theta_r)
F(1)=R*sin(theta_r)+L3*sin(x(1))-L5*sin(x(2));
F(2)= R*cos(theta_r)+L3*cos(x(1))-L5*cos(x(2))-L4;
end
for b = 1:numl(theta_r)
x(b,:)=fsolve(@(x)value(x,theta_r(b),[1,0]));
end

Akzeptierte Antwort

Jan
Jan am 20 Mai 2021
Bearbeitet: Jan am 21 Mai 2021
global R L3 L4 L5
R=80; L5=360; L4=360; L3=120; n=2; m=100*n;
theta_r=linspace(0,2*pi*n,m);
for b = 1:numel(theta_r) % fixed: "numl"
x(b,:) = fsolve(@(x) value(x, theta_r(b)), [1,0]);
end
function F = value(x,theta_r)
global R L3 L4 L5
F(1)=R*sin(theta_r)+L3*sin(x(1))-L5*sin(x(2));
F(2)= R*cos(theta_r)+L3*cos(x(1))-L5*cos(x(2))-L4;
end
  5 Kommentare
Jan
Jan am 21 Mai 2021
@Torsten: A good idea.
Luqman Alabri
Luqman Alabri am 21 Mai 2021
Thank you all.

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