Filter löschen
Filter löschen

Correlation coefficent for vectors (of unequal lengths).

25 Ansichten (letzte 30 Tage)
Anna am 25 Jul. 2013
I have two separate vectors (A and B) which I want to caculate '[r,p] = corrcoef(A,B)' for. They are the same length but both contain 'NaN' so I can't use corrcoef. Both vectors follow a time series so I can't remove the nans separately in each vector as the rows of data will then be out of sequence.
Is there a way of removing an entire row in both A and B if one of them contains a nan on a particular row so that they remain in synch with each other?
If not is there another method I can use?

Akzeptierte Antwort

Daniel Shub
Daniel Shub am 25 Jul. 2013
Bearbeitet: Daniel Shub am 25 Jul. 2013
First make some dummy data
A = 1:10;
A(2) = nan;
B = 1:10;
Then combine the arrays into a matrix so it is easy to work with
C = [A; B];
Then only keep columns for which not any of the rows are nan
D = C(:, ~any(isnan(C)))
Finally split the matrix into two new arrays
Aprime = D(1, :);
Bprime = D(2, :);

Weitere Antworten (1)

Narges M
Narges M am 25 Jul. 2013
use isnan() function to skip those rows
  5 Kommentare
Narges M
Narges M am 25 Jul. 2013
the ~isnan(A) function will give you 1s for numbers and 0s for nan elements. by adding the two together (assuming your A and B matrix are exactly the same length), you will get 2s on those rows containing numbers in both A and B. using find() function you would have that index in the number form.
so for example:
A = [ 1 4 7 NaN 8 NaN 3];
B = [NaN 6 4 5 1 NaN 9];
idx = find(~isnan(A)+ ~isnan(B)==2)
will give you:
idx = [2 3 5 7];
which is correct. now you can use
Anna am 25 Jul. 2013
Oh I see that clearly now! Thanks!

Melden Sie sich an, um zu kommentieren.


Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by