ploting 2d graph of a vector

6 Ansichten (letzte 30 Tage)
adam hafzadi
adam hafzadi am 14 Mai 2021
Bearbeitet: adam hafzadi am 15 Mai 2021
Hey Friends,
I am trying to plot a vecotr (a solution of deritinal eqution) somting like those:
x(t)=Aexp(-3t)
y(t)=Bexp(2t)
Where A B are contecst ( so i am trying to see serveral function)
thanks a lot, Adam.

Akzeptierte Antwort

Chad Greene
Chad Greene am 14 Mai 2021
You've pretty much got it, but you'll need to define a range of t values, and a value for the constants A, and B. You also need to use the * symbol for multiplication.
t = 0:0.1:10; % a range of t values from 0 to 100, steps of 0.1
A = 1;
B = 2;
x=A*exp(-3*t);
y=B*exp(2*t);
plot(t,x)
hold on
plot(t,y)
legend('x(t)','y(t)')
You may also want to set the vertical scale to log scale:
set(gca,'yscale','log')

Weitere Antworten (1)

adam hafzadi
adam hafzadi am 14 Mai 2021
oh thank you , but when i am trying to do somtig more seresis its dosn`t work
t = -100:0.1:100; % a range of t values from 0 to 100, steps of 0.1
A = 1;
B = 2;
x=A*exp(-2*t)+B*t*exp(-2*t);
y=A*exp(2*t)+B*t*exp(-2*t)+B*exp(-2*t);
plot(t,x)
hold on
plot(t,y)
legend('x(t)','y(t)')
  2 Kommentare
Chad Greene
Chad Greene am 14 Mai 2021
Oh, yes, that's a quirk of Matlab when you multiply or divide vectors. By default Matlab tries to do a "cross multiplication". To do "dot multiplication" instead, just put a period (.) in front of every multiplication symbol, like this:
t = -100:0.1:100; % a range of t values from -100 to 100, steps of 0.1
A = 1;
B = 2;
x=A.*exp(-2.*t)+B.*t.*exp(-2.*t);
y=A.*exp(2.*t)+B.*t.*exp(-2.*t)+B.*exp(-2.*t);
plot(t,x)
hold on
plot(t,y)
legend('x(t)','y(t)')
adam hafzadi
adam hafzadi am 15 Mai 2021
Bearbeitet: adam hafzadi am 15 Mai 2021
thanks a lot!

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Mathematics finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by