I want to plot y=sin x,0≤ x ≤ 2π, with 300 linear space points interval in 3D. Im kinda new to matlab, so i the read help center to learn how to do plot 3d graph. Can someone help me check it if it correct or not?
x=linspace(0,2*pi,300);
[x,y]=mehsgrid(x);
z=sin(x);
surf(x,y,z)

 Akzeptierte Antwort

DGM
DGM am 8 Mai 2021

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What did you get when you ran it? Whether it's "right" depends on what the goal is.
% this plots the surface over both x and y
% z is invariant over y
x = linspace(0,2*pi,300);
[x,y]=meshgrid(x); % spelled right
z = sin(x);
surf(x,y,z)
% this plots z for y=0
x = linspace(0,2*pi,300);
y = zeros(size(x));
z = sin(x);
plot3(x,y,z)
Depends what you want.

1 Kommentar

Amril Luqman
Amril Luqman am 8 Mai 2021
Ohh.. i want the graph to looks like the second one. Thank you very much for the help!!

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