Fading channel coefficient calculation

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Shubham
Shubham am 12 Jul. 2013
Kommentiert: jagan shanmukha am 17 Feb. 2020
I want to generate coefficient h for Nakagami channel. But, when I use gamrand() function for that, I get values greater than 1.
In the eq. r(t) = hs(t) + n(t), I don't think h should be greater than 1. So what else do I have to do in order to generate h?
  1 Kommentar
ponvignesh shanmugam
ponvignesh shanmugam am 7 Feb. 2017
r(t) = hs(t) + n(t) what does this mean? could you please explain

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Antworten (2)

Pourya Alinezhad
Pourya Alinezhad am 12 Jul. 2013
Bearbeitet: Pourya Alinezhad am 12 Jul. 2013
hi, for generating Rayleigh channel we can code as below:
h1=sqrt(0.5)*(randn+1i*randn)*(1/sqrt(2));%rayleigh channel
h2=sqrt(0.5)*(randn+1i*randn)*(1/sqrt(2));%rayleigh channel
h=[h1 0 0 0 0 h2];
for a 6 tap channel.
i don't know what the function "gamrand()" you just mentioned is?.but anyway i think you've d forget to normalize your coefficients.
  2 Kommentare
Shubham
Shubham am 13 Jul. 2013
Ok thanks. And sorry the function was gamrnd()
jagan shanmukha
jagan shanmukha am 17 Feb. 2020
Could you please tell me how to implement the above for weibull fading channel

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Prasannakumar Goli
Prasannakumar Goli am 19 Feb. 2015
Hi, yup., it is correct for rayleigh fading. but for rician can you please write coefficient?
  1 Kommentar
Akhil Singh
Akhil Singh am 3 Sep. 2019
Hey, do you know how to generate coefficient for rician fading ?

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