how to find value of variable in natural logarithmic
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How to find value of X:
ln(X/0.466)*66.66+X*4.4805*10^(-4)+X=5.66
4 Kommentare
Star Strider
am 30 Apr. 2021
I would use fsolve, since it would appear to have at most only one root.
Remember to use log, not ln in your code.
Antworten (1)
DGM
am 30 Apr. 2021
Bearbeitet: DGM
am 30 Apr. 2021
This can be done a number of ways. It's a log plus a positive linear function of x. There will be only one solution. That makes everything easier.
% solving symbolically
syms X
eqn = log(X/0.466)*66.66+X*4.4805*10^(-4)+X==5.66;
aaa = double(solve(eqn,X))
% or using fsolve
f = @(x) log(x/0.466)*66.66 + x*4.4805*10^(-4) + x - 5.66;
bbb = fsolve(f,1)
% or using fzero
ccc = fzero(f,1)
% do the answers make sense? check it graphically
x = linspace(0.2,1,100);
y = log(x/0.466)*66.66 + x*4.4805*10^(-4) + x;
plot(x,y); hold on
plot([0.2 1],[1 1]*5.66)
plot(aaa,5.66,'bo')
plot(bbb,5.66,'ko','markersize',10)
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