Optimization of the given set of equation
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
How to optimize the equation with following constraints
Here our objective function is
where the ranges of ,
Further set of constraints are
and
- , for and for
- , for all n
condition of c are
- when
- when
- when
0 Kommentare
Antworten (1)
Nipun
am 22 Mai 2024
Hi Sudhir,
I understand that you are trying to optimize the given equation with the specified constraints.
Here is the MATLAB code to solve this optimization problem:
% Define the ranges for B and V
B = 1:1:5;
V = 3.5:0.01:5;
% Pre-allocate the matrix to store results
results = zeros(length(B), length(V));
% Iterate over each combination of B and V
for i = 1:length(B)
for j = 1:length(V)
b = B(i);
v = V(j);
% Define tc based on the given constraints
n = 4; % Example value of n, can be varied as needed
if n < 3
f2 = 0;
else
if n > 3
c = 2; % Example value, vary as per conditions
if n >= 6 && n <= 10
c = 3;
elseif n > 10 && n <= 15
c = 4;
end
f2 = 4042.5 * c / (n - 3);
else
f2 = 0;
end
end
f1 = 404250 / n;
v1 = 6240 * v * b;
v2 = 1803.3 * b;
tc = v1 + v2 + f1 + f2;
% Calculate the objective function
Cop = tc / (280.8 * v * b);
% Store the result
results(i, j) = Cop;
end
end
% Find the minimum value of the objective function and its indices
[minCop, idx] = min(results(:));
[row, col] = ind2sub(size(results), idx);
% Get the optimal B and V values
optimalB = B(row);
optimalV = V(col);
% Display the results
fprintf('The minimum value of Cop is: %.4f\n', minCop);
fprintf('This occurs at B = %.2f and V = %.2f\n', optimalB, optimalV);
This code iterates over all combinations of 𝐵 and 𝑉, computes the objective function 𝐶𝑜𝑝 for each combination while considering the constraints, and finds the optimal values that minimize 𝐶𝑜𝑝. Adjust the value of 𝑛 as needed based on the specific scenario.
Hope this helps.
Regards,
Nipun
0 Kommentare
Siehe auch
Kategorien
Mehr zu Get Started with Optimization Toolbox finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!