How to delete the row from cell array?

191 Ansichten (letzte 30 Tage)
siddhesh rane
siddhesh rane am 10 Jul. 2013
Kommentiert: Kris Hoffman am 5 Jul. 2022
I have a cell arraywhich has 10*6 matrix in it. How can I delete a row from the matrix? thanks in advance.

Akzeptierte Antwort

Matt J
Matt J am 10 Jul. 2013
Is this what you want:
>> A(1:2)={rand(10,6)}
A =
[10x6 double] [10x6 double]
>> row=2; A{1}(2,:)=[] %delete 1 row from 1 cell
A =
[9x6 double] [10x6 double]
  4 Kommentare
Stephen23
Stephen23 am 28 Sep. 2018
@Ram: you will have to use a loop.
Matt J
Matt J am 28 Sep. 2018
As Stephen says, you will have to use a loop, but you can also hide the loop with cellfun,
cellfun(@(c) c(1:800), yourCell, 'uni',0 )

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (3)

Azzi Abdelmalek
Azzi Abdelmalek am 10 Jul. 2013
row=2
A(row,:)=[]
  6 Kommentare
Tong Zhao
Tong Zhao am 16 Jun. 2022
Thanks from 2022
Kris Hoffman
Kris Hoffman am 5 Jul. 2022
Thanks from 2026

Melden Sie sich an, um zu kommentieren.


John
John am 10 Jul. 2013
Bearbeitet: John am 10 Jul. 2013
You can index out the rows like any standard array (the following code removes the second row):
x = {1 2 3; 4 5 6; 7 8 9}
x =
[1] [2] [3]
[4] [5] [6]
[7] [8] [9]
y = x([1 3],:)
y =
[1] [2] [3]
[7] [8] [9]
  3 Kommentare
John
John am 10 Jul. 2013
Ok I think I understand, you have a cell array that looks like the following:
A = {rand(5), 1}
A =
[5x5 double] [1]
You want to remove a row from the matrix in the first element of A. You can do the following:
A{1} = A{1}([1 2 4 5],1);
(this will remove the third row). Alternatively you can use Azzi Abdelmalek's method shown below:
A{1}(3,:) = []
I think this is what you are looking for.
siddhesh rane
siddhesh rane am 10 Jul. 2013
thank you!! :)

Melden Sie sich an, um zu kommentieren.


siddhesh rane
siddhesh rane am 10 Jul. 2013
[A] [B] [C]
suppose i have 1*3 cell as shown above and A is a matrix of dimensions 3*3 and I want to delete second row of the A matrix. How should i do it?

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by