fill in zeros in a matrix

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Mate 2u
Mate 2u am 9 Jul. 2013
Hi all, I have a 1000x1 double matrix. It is full of numbers....but on some situations I get multiple 0s.
Whenever I encounter 0's, I want to fill the zeros with the average of the two numbers (the nearest non zero numbers above and below).
For example, if we had 3, 4, 0 ,3 , 2, 2, 0 ,0, 0, 3, 2, 1
we would get 3, 4, 3.5, 3, 2, 2, 2.5, 2.5, 2.5, 3, 2, 1.
The shorter and faster the code, the better....please remember the amount of consecutive zeros vary.

Akzeptierte Antwort

Jan
Jan am 10 Jul. 2013
x = [3, 4, 0 ,3 , 2, 2, 0 ,0, 0, 3, 2, 1];
m = (x == 0);
x(m) = interp1(find(~m), x(~m), find(m));

Weitere Antworten (1)

Matt J
Matt J am 9 Jul. 2013
I would recommend replacing the zeros with NaNs and using something like this,
instead.
  1 Kommentar
Mate 2u
Mate 2u am 9 Jul. 2013
Hi, looking for something much shorter and easier to implement, as it was a interview question....and would be nice to have something short which I can remember.

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