Filter löschen
Filter löschen

How to construct a matrix values by its row or column indexes?

11 Ansichten (letzte 30 Tage)
Antonio Trujillo-Ortiz
Antonio Trujillo-Ortiz am 9 Jul. 2013
Hi all,
I need your help on this. Suppose we have a 4x3 matrix and we need to construct a metrix with its row and column indexes as follows,
R = 1 1 1; 2 2 2; 3 3 3; 4 4 4
C= 1 2 3; 1 2 3; 1 2 3; 1 2 3
Thx in advance.

Antworten (3)

Evan
Evan am 9 Jul. 2013
Bearbeitet: Evan am 9 Jul. 2013
A(sub2ind(size(A),R,C))
Example:
>>A = magic(4);
>>R = [1 1 1; 2 2 2; 3 3 3; 4 4 4];
>>C = [1 2 3; 1 2 3; 1 2 3; 1 2 3];
>>B = A(sub2ind(size(A),R,C))
B =
16 2 3
5 11 10
9 7 6
4 14 15
If you're not talking about a generalized case and just want that particular indexing of any matrix, though, it looks like you just need to trim off part of the matrix:
>>B = A(1:4,1:3);
B =
16 2 3
5 11 10
9 7 6
4 14 15
  2 Kommentare
Antonio Trujillo-Ortiz
Antonio Trujillo-Ortiz am 9 Jul. 2013
Hi Evan,
What I need is to get from any matrix, two new ones with its row and column indexes. I mean,
Eg, given
A = [2 5 6;12 7 0;2 9 7;4 17 1 0]
we have 4 rows and 3 columns, and we need to get matrices
R = [1 1 1;2 2 2;3 3 3;4 4 4]
and
C = [1 2 3;1 2 3;1 2 3;1 2 3]
Thx
Evan
Evan am 9 Jul. 2013
Bearbeitet: Evan am 9 Jul. 2013
Ah, okay. So the row and column indices of every element in your array? I have submitted a new answer below that does this. Note that it looks like your example is for a 3x4 matrix, though, not a 4x3.

Melden Sie sich an, um zu kommentieren.


Evan
Evan am 9 Jul. 2013
Bearbeitet: Evan am 9 Jul. 2013
[R C] = find(A);

Matt J
Matt J am 9 Jul. 2013
[R,C]=ndgrid(1:size(A,1), 1:size(A,2))
  2 Kommentare
Antonio Trujillo-Ortiz
Antonio Trujillo-Ortiz am 9 Jul. 2013
Thanks Matt J. Its just what I need.
Matt J
Matt J am 9 Jul. 2013
Bearbeitet: Matt J am 9 Jul. 2013
Clicking on "Accept this answer" is all the thanks I need ;)

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by