how to preform Laplace transform?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
for i=late+1:length(x)
delayed_signal(i) = x(i)+alpha*x(i-late);
end
app.y = delayed_signal;
app.x_n = x;
x_s = laplace(x);
y_s = laplace(delayed_signal);
h_s = x_s/y_s;
I am tring to Laplace tranform the variable 'x': a .wav folder, read through 'audioread
and 'y' the same file with an echo, and then divide them and put them in 'h_s', but I keep getting the following error at the line where I define 'y_s'
Undefined function 'laplace' for input arguments of type 'double'
can someone please explain what this line means and how to fix it? - TIA
0 Kommentare
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!