Filter löschen
Filter löschen

Problem with mathematical operations

2 Ansichten (letzte 30 Tage)
francis
francis am 6 Jul. 2013
I am having trouble putting this together on matlab
t=0:0.05:.35
v(t)=sqrt((0.0035*(1440)*9.81)/0.0018)*tanh(sqrt(0.0335*(1440)*9.81*0.0018)/(0.035*2700).*t)
all of that is times t and then tanh(t) I tried to work it out and the book says the result a t=0.35 is 0.5120m/s what am I doing wrong thanks for the help

Akzeptierte Antwort

the cyclist
the cyclist am 6 Jul. 2013
Bearbeitet: the cyclist am 6 Jul. 2013
I see one specific problem with your code, and a couple potential ones. To help myself see what's going on, I rewrote your code, using parameters instead of inserting repeated numbers into the equation:
t = 0:0.05:.35;
c1 = 0.0035;
c2 = 0.0335;
c3 = 0.035;
a = 1440;
g = 9.81;
b = 0.0018;
d = 2700;
v = sqrt(c1*a*g/b) * tanh(sqrt(c2*a*g*b)/(c3*d).*t);
Notice that I changed v(t) to just v. You are not making a function here, but instead are calculating values of v. [That was probably giving you a syntax error.]
One thing I notice that I find likely to be an typo on your part is that your equation has the three different values that I called c1, c2, c3. Are any of those typos?

Weitere Antworten (1)

francis
francis am 6 Jul. 2013
Bearbeitet: the cyclist am 7 Jul. 2013
its the problem 3.6 of the matlab book pg 87
r=0.2;
vl=(4/3)*pi()*r^3;
t=0:0.05:0.35;
q=sqrt((vl*1440*9.81)/(0.0018))*tanh(sqrt(vl*1440*9.81*0.0018)/(2700*vl).*t)
the problem was to find the volume of the sphere with the radius of 0.2, I got 0.0335 , I have been checking and still got 0.35s 1.832 velocity
  4 Kommentare
the cyclist
the cyclist am 7 Jul. 2013
Found it.
You have an error in your units. The radius of the sphere is 0.2 cm, not 0.2 m.
francis
francis am 7 Jul. 2013
thank you so much,that was the last thing I would of had thought

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by