Filter löschen
Filter löschen

Function definition using a variable from a block based on a for loop

2 Ansichten (letzte 30 Tage)
Hi!
I would like to create a function in which the definition changes according to a for loop.
I have 2 row vectors from which I want to use values:
A=[1 2 3 4 5 6 7 8 9 10]
Att=[0 2 4 6 8 10 12 14 16 18]
An example:
function [a]=myf(Att)
a=Att(ii)*A(ii);
end
I would like to use the first elements of A and Att in the first cycle then the second and so on. My real function is a bit more complicated, my question is how can I change the variable inside the function according to a for loop.
Thank you!
  1 Kommentar
Gábor Dupák
Gábor Dupák am 22 Apr. 2021
Oh and I know that it can be solved without using a function, but I MUST use a function ! :)

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Steven Lord
Steven Lord am 22 Apr. 2021
For this I'd use one of two approaches.
A=[1 2 3 4 5 6 7 8 9 10];
Att=[0 2 4 6 8 10 12 14 16 18];
% Approach 1
y = myf1(Att, A);
for k = 1:numel(Att)
fprintf("Element %d of the result is %d\n", k, y(k))
end
Element 1 of the result is 0 Element 2 of the result is 4 Element 3 of the result is 12 Element 4 of the result is 24 Element 5 of the result is 40 Element 6 of the result is 60 Element 7 of the result is 84 Element 8 of the result is 112 Element 9 of the result is 144 Element 10 of the result is 180
% Approach 2
for k = 1:numel(Att)
y = myf2(Att, A, k);
fprintf("Element %d of the result is %d\n", k, y)
end
Element 1 of the result is 0 Element 2 of the result is 4 Element 3 of the result is 12 Element 4 of the result is 24 Element 5 of the result is 40 Element 6 of the result is 60 Element 7 of the result is 84 Element 8 of the result is 112 Element 9 of the result is 144 Element 10 of the result is 180
function a=myf1(Att, A)
a=Att.*A;
end
function a=myf2(Att, A, ii)
a=Att(ii)*A(ii);
end
  2 Kommentare
Gábor Dupák
Gábor Dupák am 22 Apr. 2021
Thank you! And how I can store the results in a row vector? It would be very helpful for me :)
Gábor Dupák
Gábor Dupák am 22 Apr. 2021
Oh I solved it ! Your help was awesome !

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Produkte


Version

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by