Why each time algorithm "interior point" is shown in output even if I use different algorithm?

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My fitness function is as below:
function out=myfitness(b)
u = [1 2 3 4];
out1 = u-b;
out = sum(out1.^2,2);
end
When I use the following code
clear all
clc
FUN = @myfitness;
%OPTIONS =optimoptions('fmincon','Algorithm','sqp'); % For SQP
%OPTIONS =optimoptions('fmincon','Algorithm','sqp-legacy'); % For SQP-Legacy
%OPTIONS =optimoptions('fmincon','Algorithm','trust-region-reflective'); % For Trust-region reflective
OPTIONS =optimoptions('fmincon','Algorithm','active-set'); % For Active Set
xo = [pi/2 pi/2 pi/2 pi/2]; % Starting point
%[x,fval] = patternsearch(ObjectiveFunction,x0); % For patternsearch
[x,fval,exitflag,output]= fmincon(FUN,xo);
It gives me my result. But when I check output variable "output", I see that each time "interior-point" is written in the algorithm inspite of the fact I use active-set or sqp or sqp-legacy i.e.,
output =
struct with fields:
iterations: 2
funcCount: 15
constrviolation: 0
stepsize: 2.9075
algorithm: 'interior-point'
firstorderopt: 3.9890e-08
cgiterations: 0
message: 'Local minimum found that satisfies the constra…'
Why it is so?

Akzeptierte Antwort

Alan Weiss
Alan Weiss am 22 Apr. 2021
You didn't pass the options to fmincon.
[x,fval,exitflag,output]= fmincon(FUN,xo,[],[],[],[],[],[],[],OPTIONS);
Alan Weiss
MATLAB mathematical toolbox documentation
  8 Kommentare
Walter Roberson
Walter Roberson am 22 Apr. 2021
I will not be at my desk for several hours; I answered the part that I knew from memory.

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