Runge-Kutta 2

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Nagy Csaba Norbert
Nagy Csaba Norbert am 21 Apr. 2021
Hi, i have a homwork for school including the Runge-Kutta 2.
I have to do it in symbolic, i would be very greatfull if someone can help me in this taks.
intervalmin = 0;
intervalmax = 1;
h1 = 0.1;
g = 0.02;
X0 = [0, 0];
[t1, x1] = fuggveny(intervalmin, X0(1), X0(2), h1, intervalmax);
[t2, x2] = fuggveny(intervalmin, X0(1), X0(2), g, intervalmax);
syms x(t);
dz = diff(x,t);
ode = diff(x,t,2) + 5.*diff(x,t,1) + 4.*x(t) == 3 - 2.*t - t.^2;
cond1 = x(0) == 1;
cond2 = dz(0) == 1;
RK2(t) = dsolve(ode,cond1,cond2);
plot(t1, x1, '-y');
hold on;
plot(t2, x2, '--r');
hold on;
fplot(RK2,'-*b');
hold on
legend('h=0.1','h=0.02','ode')
ax = gca;
ax.XAxisLocation = 'origin';
ax.YAxisLocation = 'origin';
grid on;
function dX = f(t, x1, x2)
X1 = x2;
X2 = -5.*x2 + 4.*x1 + 3 - 2.*t - t.^2;
dX = [X1, X2];
end
function [t, x] = fuggveny(intervalmin, X0_1, X0_2, h, intervalmax)
t = (intervalmin:h:intervalmax);
X1 = zeros(size(t));
X2 = zeros(size(t));
X1(1) = X0_1;
X2(1) = X0_2;
for i = 1:1:length(t) - 1
k1 = f(t(i), X1(i), X2(i));
k2 = f(t(i) + h/2, X1(i) + h/2 * k1(1), X2(i) + h/2 * k1(2));
k3 = f(t(i) + h, X1(i) - h*k1(1) + 2*h*k2(1), X2(i) - h*k1(2) + 2*h*k2(2));
X1(i + 1) = X1(i) + h/6 * (k1(1) + 4*k2(1) + k3(1));
X2(i + 1) = X2(i) + h/6 * (k1(2) + 4*k2(2) + k3(2));
end
x = X1;
end

Akzeptierte Antwort

James Tursa
James Tursa am 21 Apr. 2021
Bearbeitet: James Tursa am 21 Apr. 2021
The + 4.*x1 should be - 4.*x1 in your derivative function. Also, using both X1 and x1 and X2 and x2, even though MATLAB is case sensitive and these are different variables, is confusing to read. Suggest using different names such as x1dot and x2dot, or even just form the derivative vector directly. E.g.,
function dX = f(t, x1, x2)
dX = [x2; -5.*x2 - 4.*x1 + 3 - 2.*t - t.^2];
end
Also, just to clarify, you are asked to solve this both symbolically and numerically?
Not sure why the assignment says Runge-Kutta II when it looks like you are using a 3rd order method.
  3 Kommentare
James Tursa
James Tursa am 22 Apr. 2021
Are you getting errors? The output is not what you expected? Or ...?
Nagy Csaba Norbert
Nagy Csaba Norbert am 22 Apr. 2021
I don't get any error messages. The problem is that, i don't know what the output should to be look like. My teacher noticed my work with that comment, "there are too many X s in my task.

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