how can I solve this problem..
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
syms theta0
th = -y+cos(theta0)*x^2-g*x^2/(2*v0^2*sin(theta0)^2) == 0;
theta0 = [0 pi];
stheta0 = fzero(th,theta0);
I want to get two roots for theta0 but when I erased 'theta0 = [0 pi]' , it was too complicated.
0 Kommentare
Antworten (1)
John D'Errico
am 20 Apr. 2021
Bearbeitet: John D'Errico
am 20 Apr. 2021
Um, what do you expect?
syms theta0
x=90; g=9.81; v0=30; y0=1.8; y=1;
th = -y+tan(theta0)*x-g*x^2/(2*v0^2*cos(theta0)^2)+y0;
pretty(th)
Do you expect an analytical solution, something nice and simple and very pretty?
thsol = solve(th)
You should be able to effectively reduce this to effectively a 4th degree polynomial in terms of sin(theta0), so 4 roots.
vpa(thsol)
There are probably infinitely many solutions since trig functions are periodic. I don't see how much better than that you can rationally expect? Honestly, I'd say you are pretty lucky, in that solutions are easily generated\. Just pick the one that makes sense to you.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Particle & Nuclear Physics finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!