In table, how to select values in one column based on values in another column?
39 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Doheon Lee
am 17 Apr. 2021
Kommentiert: Doheon Lee
am 20 Apr. 2021
As given in the title, I like to call values in one table based on values in anothe column. I have a follwoing table.
T = table({'a'; 'b'; 'c'; 'd'; 'e'}, [1;2;3;4;5], 'variablenames', {'name', 'value'});
I like to call elements in the 'value' column, for 'd', 'b', 'e' in the 'name' column. So the expected result is as below
result =
4.00
2.00
5.00
I can do this with the following codes.
order = {'d', 'b', 'e'};
[Lia, Locb] = ismember(T.name, order);
order_chosen = T.value(Lia);
Locb = nonzeros(Locb);
result = order_chosen(Locb);
However, as you can see, lines seem too many for such a relatively simple outcome. So I wonder if there is way to do the samething efficiently with shorter lines.
Thank you for any help in advance.
0 Kommentare
Akzeptierte Antwort
Cris LaPierre
am 17 Apr. 2021
The simplest way to do this is using logical indexing, but that doesn't preserve the order. That makes it a more challenging problem to solve. Still, it can be done in fewer lines. I suggest using find.
T = table({'a'; 'b'; 'c'; 'd'; 'e'}, [1;2;3;4;5], 'variablenames', {'name', 'value'});
% Find rows corresponding to names, preserving order
[rows,~]=find(T.name==["d","b","e"]);
result = T(rows,"value")
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu LaTeX finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!