Filter löschen
Filter löschen

Finding tangent plane with the max range value and z value being equal

1 Ansicht (letzte 30 Tage)
Hi there. I'm plotting a tangent plane to a particular surface. However, the range for both x and y if +- sqrt(2), which is +-1.41. The expected value of z for the tangent plane is sqrt(2) as well. However, when i run the command, MATLAB produces an error for that particulat range (produces sucessful output on ranges such as +-2). Would be grateful if someone provided insight what I could do to solve this issue. The code is shown below. Any advice would be greatly apreciated.

Akzeptierte Antwort

Andrew Newell
Andrew Newell am 16 Apr. 2021
Bearbeitet: Andrew Newell am 16 Apr. 2021
Notice that j is empty, then try this:
X = -1.41:0.01:1.41;
[~,idx] = min(abs(X-1));
This being floating point, you're not getting exact increments of . You could scale everything so x, y are and then find and . Or you could do it like this:
z = @(x,y) sqrt(4-x.^2-y.^2);
X = -1.41:0.01:1.41;
[x,y] = meshgrid(X);
[fx,fy] = gradient(z(x,y),0.01);
[~,j] = min(abs(X-1));
fx0 = fx(j,j);
fy0 = fy(j,j);
z1 = @(x,y) z(1,1) + fx0*(x-1) + fy0*(y-1);
As a side note, you don't need . You can use j directly as logical indexing.

Weitere Antworten (0)


Mehr zu Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by